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crimeas [40]
2 years ago
5

Helppppppppppppp:))))

Mathematics
1 answer:
liubo4ka [24]2 years ago
4 0

<h2><em><u>Pl</u></em><em><u>ease</u></em><em><u> mark</u></em><em><u> my</u></em><em><u> answer</u></em><em><u> the</u></em><em><u> brainliest</u></em><em><u> and</u></em><em><u> rate</u></em><em><u> me</u></em><em><u> 5</u></em><em><u> star</u></em><em><u> and</u></em><em><u> follow</u></em><em><u> me</u></em><em><u>.</u></em></h2>

<em><u>ple</u></em><em><u>ase</u></em><em><u> please</u></em><em><u> please</u></em><em><u> please</u></em><em><u> please</u></em><em><u> please</u></em><em><u> </u></em>

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A box of donuts containing 6 maple bars, 3 chocolate donuts, and 3 custard filled donuts is sitting on a counter in a work offic
Svetlanka [38]

Probabilities are used to determine the chances of selecting a kind of donut from the box.

The probability that Warren eats a chocolate donut, and then a custard filled donut is 0.068

The given parameters are:

\mathbf{Bars = 6}

\mathbf{Chocolate = 3}

\mathbf{Custard= 3}

The total number of donuts in the box is:

\mathbf{Total= 6 + 3 + 3}

\mathbf{Total= 12}

The probability of eating a chocolate donut, and then a custard filled donut is calculated using:

\mathbf{Pr = \frac{Chocolate}{Total}\times \frac{Custard}{Total-1}}

So, we have:

\mathbf{Pr = \frac{3}{12}\times \frac{3}{12-1}}

Simplify

\mathbf{Pr = \frac{3}{12}\times \frac{3}{11}}

Multiply

\mathbf{Pr = \frac{9}{132}}

Divide

\mathbf{Pr = 0.068}

Hence, the probability that Warren eats a chocolate donut, and then a custard filled donut is approximately 0.068

Read more about probabilities at:

brainly.com/question/9000575

7 0
2 years ago
Can someone solve this question PLEASE?? check the attached pic
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Step-by-step explanation:

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What is the value of the expression?
Lady bird [3.3K]

Answer:

690

Step-by-step explanation:

(323+1715)-(1135+213)

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5 0
3 years ago
Hello, can you help me with a probability question, please:)​
sladkih [1.3K]
Ok what is it that u need
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2 years ago
Answer please.. I need help
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When you set the denominators of 2 / 5 and 1 / 3, equal to each other, you receive a denominator of 15, the only denominator the two have in common
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