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Sidana [21]
2 years ago
15

The circumference of a circle is 69.08 meters. What is the circle's radius? Use 3.14 for ​.

Mathematics
2 answers:
Nezavi [6.7K]2 years ago
7 0

Answer:

Circumference = 2πr

69.08 = 2× 3.14 × r

69.08 ÷ 6.28 = r

11m = r

Inessa05 [86]2 years ago
7 0

Answer: 22

Step-by-step explanation: Divide the total by pi or 3.14 and the diameter is 22 and the radius is 11

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Anyone know how to do this? i dont know how to get the whole angle including 44 and P
Ganezh [65]

Answer:

C

Step-by-step explanation:

The total circumference = 5*2 pi = 10pi

You are trying to find (360-44)/360 of the circumference, which simplifies to 79/90.

79/90 *10pi =

79pi/9, which is C

4 0
3 years ago
Pls help me with this!
joja [24]

Answer:

A = 78.5 cm²

Step-by-step explanation:

Area = π · radius²

if diameter is 10 then radius is 5

A = 5²·π

A = 25 × 3.14

A = 78.5 cm²

6 0
3 years ago
A bag contains 6 yellow marbles and 18 red. If a representative sample contains 2 yellow marbles, then how many red would you ex
kramer

Answer:

6 red marbles

Step-by-step explanation:

We must first find our multiplier since a sample represents a population (the whole thing).

6/2 = 3, so 3 * 2 = 6.

I will use the value of 6/2, aka 3 and use that as my divisor.

18/3 = 6.

Therefore, you would expect to have 6 red marbles.

3 0
3 years ago
The vertices of a rectangle are A(-4,-3) b(-4,-1)C(-1,-1)d(-1,-3)
Vesnalui [34]

Answer:

Step-by-step explanation:

a: A(4,-3) B(4,-1) C(1,-1) D(1,-3)

b: A(-4,3) B(-4,1) C(-1,1) D(-1, 3)

c:yes because you are just changing the direction not the shape or size

4 0
3 years ago
A species of beetles grows 32% every year. Suppose 100 beetles are released into a field. How many beetles will there be in 10 y
siniylev [52]

Given that a species of beetles grows 32% every year.

So growth rate is given by

r=32%= 0.32


Given that 100 beetles are released into a field.

So that means initial number of beetles P=100


Now we have to find about how many beetles will there be in 10 years.

To find that we need to setup growth formula which is given by

A=P(1+r)^n where A is number of beetles at any year n.

Plug the given values into above formula we get:

A=100(1+0.32)^n

A=100(1.32)^n


now plug n=10 years

A=100(1.32)^{10}=100(16.0597696605)=1605.97696605

Hence answer is approx 1606 beetles will be there after 20 years.


Now we have to find about how many beetles will there be in 20 years.

To find that we plug n=20 years

A=100(1.32)^{20}=100(257.916201549)=25791.6201549

Hence answer is approx 25791 beetles will be there after 20 years.



Now we have to find time for 100000 beetles so plug A=100000

A=100(1.32)^n

100000=100(1.32)^n

1000=(1.32)^n

log(1000)=n*log(1.32)

\frac{\log\left(10000\right)}{\log\left(1.32\right)}=n

33.174666862=n

Hence answer is approx 33 years.

4 0
3 years ago
Read 2 more answers
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