The answer is <span>13584.1129633 which simplified is 13584 :)</span>
Answer:
0.667
Step-by-step explanation:
Angle in a circle = 360°
Area of total shaded parts = 60 + 60 = 120°
Area of total unshaded parts = 360-120 = 240°
Probability that a random selected point within the circle falls in the unshaded area
= 240/360
= 2/3
≈ 0.667
I apologize in advance if I made a mistake.
Answer:
1/2
Step-by-step explanation:
if you look at a unit circle, sin(\pi/6) is
so cos of (\pi/6/2) would be \pi/3, and cos of (\pi/3) is 1/2
Answer:
53
Step-by-step explanation:
70-17= 53
(a) First find the intersections of

and

:

So the area of

is given by

If you're not familiar with the error function

, then you will not be able to find an exact answer. Fortunately, I see this is a question on a calculator based exam, so you can use whatever built-in function you have on your calculator to evaluate the integral. You should get something around 0.5141.
(b) Find the intersections of the line

with

.

So the area of

is given by


which is approximately 1.546.
(c) The easiest method for finding the volume of the solid of revolution is via the disk method. Each cross-section of the solid is a circle with radius perpendicular to the x-axis, determined by the vertical distance from the curve

and the line

, or

. The area of any such circle is

times the square of its radius. Since the curve intersects the axis of revolution at

and

, the volume would be given by