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wolverine [178]
2 years ago
13

A crate is released from the highest point of a 12 m long ramp inclined at 60° with the horizontal. The motion is frictionless.

What is the speed of the crate at the base of the ramp?​
Physics
1 answer:
Darya [45]2 years ago
3 0

law of conservation of mechanical energy

PE1 = Ek2

mgh=1/2mv²

h = 12 sin 60

\tt v=\sqrt{2gh}=\sqrt{2\times 9.8\times 12\times sin~60}=14.27~m/s

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Answer:

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Explanation:

Given

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Required

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Since it's a parallel connection, it can be solved using.

1/Rt = 1/R1 + 1/R2

Substitute values for R1 and RT

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Collect Like Terms

1/R2 = 1/205 - 1/633

Take LCM

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1/R2 = 428/129765

Take reciprocal of both sides

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