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Furkat [3]
3 years ago
14

If the work function of a material is such that red light of wavelength 700 nm just barely initiates the photoelectric effect, w

hat must the maximum kinetic energy of ejected electrons be when violet light of wavelength 400 nm illuminates the material? Express your answer with the appropriate units.
Physics
1 answer:
marishachu [46]3 years ago
3 0

Answer:

2.13 x 10^-19 J or 0.53 eV

Explanation:

cut off wavelength, λo = 700 nm = 700 x 10^-9 m

λ = 400 nm = 400 x 10^-9 m

Use the energy equation

E = \frac{h c}{\lambda _{o}}+K

Where, K be the work function

\frac{h c}{\lambda} = \frac{h c}{\lambda _{o}}+K

K =hc\left ( \frac{1}{\lambda } -\frac{1}{\lambda _{0}}\right )

K =6.63\times 10^{-34}\times 3\times 10^{8}\left ( \frac{1}{4\times 10^{-7} } -\frac{1}{7\times 10^{-7}}\right )

K = 2.13 x 10^-19 J

K = 0.53 eV

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Compare the magnitudes of the electric and magnetic forces on an electron that has attained a velocity of 107 m/s. Assume an ele
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F = 1.608 x 10⁻¹⁴ N

Explanation:

Given,

The velocity of the electron, v = 10⁷ m/s

The electric field intensity, E = 10⁵ V/m

The magnetic flux density, B = 0.5 gauss

                                                = 5 x 10⁻⁵ tesla

The magnitudes of the electric and magnetic forces on an electron is given by the Lorentz force,

                                F = q (E + v x B)

Substituting the given values,

                                F = 1.6 x 10⁻¹⁹ (10⁵ + 10⁷ x 5 x 10⁻⁵)

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The relation that can be stated is E = mc²

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