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lisabon 2012 [21]
3 years ago
15

A racecar begins at rest and accelerates to 25 m/s at a rate of 6.25 m/s2. What distance does the racecar cover?

Physics
1 answer:
Vitek1552 [10]3 years ago
7 0

Answer:

d.

50 m

Explanation:

v² = u² + 2as

s = (v² - u²) / 2a

s =(25² - 0²) / (2(6.25))

s = 50 m

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<span>The 2nd truck was overloaded with a load of 16833 kg instead of the permissible load of 8000 kg. The key here is the conservation of momentum. For the first truck, the momentum is 0(5100 + 4300) The second truck has a starting momentum of 60(5100 + x) And finally, after the collision, the momentum of the whole system is 42(5100 + 4300 + 5100 + x) So let's set the equations for before and after the collision equal to each other. 0(5100 + 4300) + 60(5100 + x) = 42(5100 + 4300 + 5100 + x) And solve for x, first by adding the constant terms 0(5100 + 4300) + 60(5100 + x) = 42(14500 + x) Getting rid of the zero term 60(5100 + x) = 42(14500 + x) Distribute the 60 and the 42. 60*5100 + 60x = 42*14500 + 42x 306000 + 60x = 609000 + 42x Subtract 42x from both sides 306000 + 18x = 609000 Subtract 306000 from both sides 18x = 303000 And divide both sides by 18 x = 16833.33 So we have the 2nd truck with a load of 16833.33 kg, which is well over it's maximum permissible load of 8000 kg. Let's verify the results by plugging that mass into the before and after collision momentums. 60(5100 + 16833.33) = 60(21933.33) = 1316000 42(5100 + 4300 + 5100 + 16833.33) = 42(31333.33) = 1316000 They match. The 2nd truck was definitely over loaded.</span>
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4 years ago
Question 4 (1 point)
Valentin [98]

cardiovascular endurance :))

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A rowboat passenger uses an oar to push the boat off the dock by exerting a force of 60.0 N for 2.0s. What impulse acts on the b
NARA [144]
Impulse<span> is the change of momentum of an object when the object is acted upon by a force for an interval of time. It is simply calculated by the expression:
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Hope this answers the question. Have a nice day.
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What is the density of a block of marble that
EleoNora [17]

Explanation:

Solution,

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Mass(m)=816 g

Density(d)=m/v

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So, the density of the block of marbles is 2.84 g/cm^3.

I hope it helped U

stay safe stay happy

5 0
3 years ago
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