because y^3 is raised to the power of two, we will have to multiply the exponents rather than adding them.
By distributing the power of 2, we will get y^2(6).
Because now the exponents are being multiplied, we can just add them to get y^8. The other y has a power of 1, so we'll just add the power of that y as well to get y^9.
summary:
multiply exponents if they are being raised to a power.
add exponents if they are being multiplied, and only add them if they have the same base (in this case, both the bases of the exponents are y, so we can add them)
Answer:
Step-by-step explanation:
Given: The radius of circle O is r, and the radius of circle X is r'.
To prove: Circle O is similar to circle X.
Proof: Move the center of the smaller circle onto the center of the largest circle. Translate the circle X by the vector XA onto circle O. The circles now have the same center.
A dilation is needed to increase the size of circle X to coincide with the circle O. A value which when multiplied by r' will create r.
The scale factor x to increase X:
⇒
A translation followed by a dilation with scale factor will map one circle to the other, thus proving the given both circles similar.
Therefore, circle O is similar to circle X.
Step-by-step explanation:
Answer:
2√6
Step-by-step explanation:
I will be honest with you and say that I'm not sure if it is right or not.
Hello :)
3x+y=27
-3x+4y= -42
+____________
(3x -3x) + (y+4y) = (27-42)
0 + 5y = -15
y = -3
Put "-3" for "y" in the system:
3x + y =27
3x -3=27
3x = 30
x = 10
Answer = x:10 y: -3
Have a nice day :)
Isnt it 15?? since theyre all suppose to be the samw