R = d/t is the answer. Hope this helped
Answer: 4
Step-by-step explanation: Range is the difference between the highest and lowest number, so since 5 is the highest and 1 is the lowest you subtract 1 from 5 to get your answer: 4.
All of the answer choices that you are given are incorrect. I have calculated it in all different ways and get the same thing and it is none of those. The correct answer would be -75 though.
Answer:
If B is between A and C, AB = x, BC = 2x + 2, and AC = 14, find the value of x. Then find AB and BC.
Step-by-step explanation:
AB=x
BC = 2x + 2BC=2x+2
AC =14AC=14
Required
Determine x, AB and BC.
Since B is between A and C;
AB + BC = ACAB+BC=AC
Substitute x for AB; 2x + 2 for BC and 14 for AC
x + 2x + 2 = 14x+2x+2=14
3x + 2 = 143x+2=14
Collect Like Terms
3x = 14 - 23x=14−2
3x = 123x=12 '
x = \frac{12}{3}x=
3
12
x = 4x=4
Substitute 4 for x in
AB = xAB=x
BC = 2x + 2BC=2x+2
AB = 4AB=4
BC = 2(4) + 2BC=2(4)+2
BC = 8 + 2BC=8+2
BC = 10BC=10
<h3>
Answer: Yes they are equivalent</h3>
==============================================
Work Shown:
Expand out the first expression to get
(a-3)(2a^2 + 3a + 3)
a(2a^2 + 3a + 3) - 3(2a^2 + 3a + 3)
2a^3 + 3a^2 + 3a - 6a^2 - 9a - 9
2a^3 + (3a^2-6a^2) + (3a-9a) - 9
2a^3 - 3a^2 - 6a - 9
Divide every term by 2 so we can pull out a 2 through the distributive property
2a^3 - 3a^2 - 6a - 9 = 2(a^3 - 1.5a^2 - 3a - 4.5)
This shows that (a-3)(2a^2 + 3a + 3) is equivalent to 2(a^3 - 1.5a^2 - 3a - 4.5)