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ExtremeBDS [4]
3 years ago
12

-3(1-2x)=3x+3(x-3)+6

Mathematics
1 answer:
deff fn [24]3 years ago
6 0

Let's solve this problem step-by-step.

−3(1−2x)=3x+3(x−3)+6

Step 1: Simplify both sides of the equation.

−3(1−2x)=3x+3(x−3)+6

(−3)(1)+(−3)(−2x)=3x+(3)(x)+(3)(−3)+6(Distribute)

−3+6x=3x+3x+−9+6

6x−3=(3x+3x)+(−9+6)(Combine Like Terms)

6x−3=6x+−3

6x−3=6x−3

Step 2: Subtract 6x from both sides.

6x−3−6x=6x−3−6x

−3=−3

Step 3: Add 3 to both sides.

−3+3=−3+3

0=0

So, 0=0 or all real numbers.

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In ΔUVW, the measure of ∠W=90°, the measure of ∠V=71°, and VW = 55 feet. Find the length of UV to the nearest tenth of a foot.
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Step-by-step explanation:

7 0
3 years ago
Please Help. I really don’t get this concept, if you could explain it in detail it would be very appreciated
Dafna11 [192]
<h3>Answer: 24/25</h3>

=================================================

Explanation:

Sine is given to be negative, and so is tangent. This only happens in quadrant Q4

Recall that y = sin(theta), so if sin(theta) < 0, then we're below the x axis.

If tan(theta) < 0, then this means cos(theta) > 0

So we have y < 0 and x > 0 which places the angle somewhere in Q4.

--------------------------

Draw a right triangle as shown below in the attached image. We have AC = 25 and BC = 7. Use the pythagorean theorem to find that AB = 24

So this is what your steps may look like

a^2+b^2 = c^2

7^2+b^2 = 25^2

b^2+49 = 625

b^2 = 625-49

b^2 = 576

b = sqrt(576)

b = 24

So because AB = 24, we know that the cosine of the angle is adjacent/hypotenuse = 24/25

---------------------------

As an alternative, you could use the trig identity

sin^2(x) + cos^2(x) = 1

and plug in the given value of sine to solve for cosine. The cosine value result will be positive since we're in Q4.

So,

sin^2(x) + cos^2(x) = 1

(-7/25)^2 + cos^2(x) = 1

(49/625) + cos^2(x) = 1

cos^2(x) = 1 - (49/625)

cos^2(x) = (625/625) - (49/625)

cos^2(x) = (625-49)/625

cos^2(x) = 576/625

cos(x) = sqrt(576/625)

cos(x) = sqrt(576)/sqrt(625)

cos(x) = 24/25

This is effectively a rephrasing of the previous section since the pythagorean trig identity is more or less the pythagorean theorem (just in a trig form)

6 0
3 years ago
Which is greater 15/27 or 16/24
Artemon [7]

Answer:

16/24

Step-by-step explanation:

let’s use the GCF of both which is 3 for 15/27

15/27 divided by 3 is 5/9

for 16/24 the gcf is 8

16/24 / 8 is 2/3

now we have to multiply 2/3 times 3

2/3 times 3 6/3 which is 2

so 16/24 is greater.

3 0
3 years ago
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