The equation, in slope-intercept form, of the line that is perpendicular to the line y- 4 = -(x-6) and passes through the point (-2,-2) is y = x.
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<h3>How to represent equation in slope intercept form?</h3>
The equation in slope intercept form is represented as follows;
y = mx + b
where
Therefore,
perpendicular lines follows the rule as follows;
m₁m₂ = -1
Therefore,
y - 4 = -(x - 6)
y - 4 = -x + 6
y = -x + 6 + 4
y = -x + 10
Therefore,
-1m₂ = -1
m₂ = 1
Hence, the line passes through (-2, -2).
Therefore,
-2 = 1(-2) + b
b = -2 + 2
b = 0
Therefore, the equation is as follows;
y = x
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Answer:
answer is the third choice : 104
Step-by-step explanation:
Inscribed Angle Theorem
If an angle is inscribed in a circle, then the measure of the angle equals one half the measure of its intercepted arc.
so the intercepted arc is TWICE the measure of an angle inscribed in a circle
1. A central angle is an angle with endpoints located on a circle's circumference and vertex located at the circle's center. A central angle in a circle determines an arc.
2. An inscribed angle is an angle formed by three points on the circle's circumference.
Angle at the Center Theorem: An inscribed angle is half of the central angle (if they determine the same arc).
In your case angles:
1. ∠QSR is insribed (determines the arc QR);
2. ∠QTR is central (determines the arc QR).
Then by Angle at the Center Theorem, m∠QTR=2m∠QSR=2·52°=104°. Arc QR has the same measure as central angle QSR.
gathmath
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Answer:
2a +7
Step-by-step explanation: