HELPP *20 points*
1 answer:
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The customer can purchase 1.19788 pounds of cheese (approximately 1.2 pounds).
<h3>How much cheese can she purchase?</h3>We are given with the cost of ham is $2.49 per pound and
Cost of swiss cheese is $3.79 per pound.
So, the cost of 2 pounds of ham will be given as-
= 2× $2.49
= $4.98
Since, the customer has a total of $9.50 to spend on 2 pounds of ham and some cheese,
∴ Let the number of pounds of cheese she can purchase be x.
Then the equation will be this:
2.49*2 + 3.79*x = 9.50
4.98 + 3.79x = 9.50
Subtracting 4.98 from each side we get-
4.98 -4.98 + 3.79x = 9.50-4.98
3.79x = 4.54
x
x = 1.19788 pounds of cheese (approximately 1.2 pounds).
Hence, the customer can purchase 1.19788 pounds of cheese (approximately 1.2 pounds).
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The probability of 3 successes is 0.0384
<h3>How to determine the probability?</h3>The given parameters are:
- Trials, n = 4
- Probability of success, p = 0.4
The binomial probability is represented as:
So, the probability of three successes is:
Evaluate the factors in the expression
Evaluate the combination expression
P(3) = 1 * 0.0384
Evaluate the product
P(3) = 0.0384
Hence, the probability of 3 successes is 0.0384
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