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Mekhanik [1.2K]
2 years ago
11

HELPP *20 points*

Mathematics
1 answer:
aleksklad [387]2 years ago
5 0

Answer:

the answer for this problem should be half of 3.1 sense 2.5 is half of 5 so split 3.1 in have to get 1.55. hope this helps.

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What are the steps for this equation: -5x-16 = -10x-11?
sineoko [7]

Answer:

x=1

Step-by-step explanation:

-5x-16=-10x-11

+10x +10x

5x-16=-11

+16 +16

5x=5

5x/5 = 5/5

x=1

8 0
3 years ago
at a delicatessen, ham costs $2.49 per pound and swiss cheese costs $3.79 per pound. The customer has $9.50 to spend on 2 pounds
vichka [17]

The customer can purchase 1.19788 pounds of cheese (approximately 1.2 pounds).

<h3>How much cheese can she purchase?</h3>

We are given with the cost of ham is $2.49 per pound and

Cost of swiss cheese is $3.79 per pound.

So, the cost of 2 pounds of ham will be given as-

= 2× $2.49

= $4.98

Since, the customer has a total of  $9.50 to spend on 2 pounds of ham and some cheese,

∴ Let the number of pounds of cheese she can purchase be x.

Then the equation will be this:

2.49*2 + 3.79*x = 9.50

4.98 + 3.79x = 9.50

Subtracting 4.98 from each side we get-

4.98 -4.98 + 3.79x = 9.50-4.98

3.79x = 4.54

x  =\frac{4.54}{3.79}

x = 1.19788 pounds of cheese (approximately 1.2 pounds).

Hence, the customer can purchase 1.19788 pounds of cheese (approximately 1.2 pounds).

Learn more about purchase here,

brainly.com/question/2105000

#SPJ10

4 0
1 year ago
Simplify this expression.<br><br> (1-3k) + (2 + 2.5k)
Crank

(1 - 3k) + (2 + 2.5k)

= 1 - 3k + 2 + 2.5k

= (1 + 2) + ( - 3k + 2.5k)

= 3  + ( - 0.5k)

= 3 - 0.5k

7 0
3 years ago
A binomial experiment has 4 trials in which p = 0.4. What is the probability of 3 successes?
Kaylis [27]

The probability of 3 successes is 0.0384

<h3>How to determine the probability?</h3>

The given parameters are:

  • Trials,  n = 4
  • Probability of success, p = 0.4

The binomial probability is represented as:

P(x) = ^nC_x * p^x * (1 - p)^{n-x

So, the probability of three successes is:

P(3) = ^4C_3 * 0.4^3 * (1 - 0.4)^{4 -3

Evaluate the factors in the expression

P(3) = ^4C_3 * 0.0384

Evaluate the combination expression

P(3) = 1 * 0.0384

Evaluate the product

P(3) = 0.0384

Hence, the probability of 3 successes is 0.0384

Read more about probability at:

brainly.com/question/25870256

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4 0
1 year ago
The probability that a random smoker will develop a sever lung condition during his or her lifetime is 0.3. we will choose a ran
postnew [5]
The mean is 36 and the standard deviation is 5.02.

The mean is given by
μ = np = 120*0.3 = 36.

The standard deviation is given by
σ = √(n*p*(1-p)) = √(120*0.3*0.7) = √25.2 = 5.02.
8 0
3 years ago
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