Answer: ∆V for r = 10.1 to 10ft
∆V = 40πft^3 = 125.7ft^3
Approximate the change in the volume of a sphere When r changes from 10 ft to 10.1 ft, ΔV=_________
[v(r)=4/3Ï€r^3].
Step-by-step explanation:
Volume of a sphere is given by;
V = 4/3πr^3
Where r is the radius.
Change in Volume with respect to change in radius of a sphere is given by;
dV/dr = 4πr^2
V'(r) = 4πr^2
V'(10) = 400π
V'(10.1) - V'(10) ~= 0.1(400π) = 40π
Therefore change in Volume from r = 10 to 10.1 is
= 40πft^3
Of by direct substitution
∆V = 4/3π(R^3 - r^3)
Where R = 10.1ft and r = 10ft
∆V = 4/3π(10.1^3 - 10^3)
∆V = 40.4π ~= 40πft^3
And for R = 30ft to r = 10.1ft
∆V = 4/3π(30^3 - 10.1^3)
∆V = 34626.3πft^3
Answer:
<h2>C. The contributions are tax exempt because they will be taxed in the future.</h2>
Step-by-step explanation:
The type of contribution Mauricio is doing is Tax Deferred Contribution, which refers to contributions from investment earnings, like dividends, capital gains or retirements accounts, all these accumulate tax-free fees until the person receive the profits.
Therefore, the right answer here is c, because it will be taxed in the future.
Answer:
12 ounces
Step-by-step explanation:
If he drinks 3 ounces on 1/4 an hour, then all you have to do is multiply by 4
Answer:
y = (x – 6) / -3 = [2 – x/3]
Step-by-step explanation:
y = f(x) = -3x + 6
f⁻¹(x) → x = -3y + 6 → (x – 6) / -3 → x / -3 + -6/-3 → -x / 3 + 2 → 2 – x/3
If -0.14 is changed to 2, the graph would become a positive graph, or it would be steeper, because it has a positive slope
The equation of the graph is given as:
The above equation is a linear equation, which is represented as:
Where m represents the slope of the linear equation.
By comparison, we have:
i.e. the slope of the equation is -0.14
When -0.14 is replaced with 2, the equation becomes
And the slope of the new equation is
2 is greater than -0.14, and 2 is positive.
This means that the graph would become a positive graph, or it would be steeper, because it has a positive slope
Read more linear equations at:
brainly.com/question/19045223
