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kirill115 [55]
2 years ago
15

Two sides of a triangle measure

Mathematics
2 answers:
Eduardwww [97]2 years ago
8 0

Answer:

4

Step-by-step explanation:

Svetllana [295]2 years ago
5 0

Answer:

A:4cm

Step-by-step explanation:

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Help plss..................
Afina-wow [57]

The equation of a line that passes through points (0, 2) and (-2,0) is y=1x+2

8 0
3 years ago
Read 2 more answers
A random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength
irinina [24]

Answer:

Probability that the sample mean comprehensive strength exceeds 4985 psi is 0.99999.

Step-by-step explanation:

We are given that a random sample of n = 9 structural elements is tested for comprehensive strength. We know the true mean comprehensive strength μ = 5500 psi and the standard deviation is σ = 100 psi.

<u><em>Let </em></u>\bar X<u><em> = sample mean comprehensive strength</em></u>

The z-score probability distribution for sample mean is given by;

                          Z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

where, \mu = population mean comprehensive strength = 5500 psi

            \sigma = standard deviation = 100 psi

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, Probability that the sample mean comprehensive strength exceeds 4985 psi is given by = P(\bar X > 4985 psi)

    P(\bar X > 4985 psi) = P( \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n} } } > \frac{4985-5500}{\frac{100}{\sqrt{9} } } ) = P(Z > -15.45) = P(Z < 15.45)

                                                                  = <u>0.99999</u>

<em>Since in the z table the highest critical value of x for which a probability area is given is x = 4.40 which is 0.99999, so we assume that our required probability will be equal to 0.99999.</em>

4 0
3 years ago
How to do this problem??
lorasvet [3.4K]
We know that the sum of the inner angles of any triangle is 180º

72º + (7x + 3)º + (3x + 5)º = 180º
72º + 7xº + 3º + 3xº + 5º = 180
7xº + 3xº = 180º - 72º - 3º - 5º
10xº = 100º
x^0 =  \frac{100^0}{10^0}
x^0 = 10\to\:\boxed{\boxed{x = 10^0}}\end{array}}\qquad\quad\checkmark

The sum of the external angle (9y + 1)º with inner angle (3x + 5) = 180 °, <span>Replace the measure of "x" found:
</span>
(9y + 1)º + (3x + 5)º = 180º
9yº + 1º + 3xº + 5º = 180º
9yº + 1º + 3.(10)º + 5º = 180º
9yº + 1º + 30º + 5º = 180º
9yº = 180º - 1º - 30º - 5º
9yº = 144º
y^0 =  \frac{144^0}{9^0}
y^0 = 16\to\:\boxed{\boxed{y = 16^0}}\end{array}}\qquad\quad\checkmark

Answer:
<span>The measures ​​of "x" and "y" are respectively: 10º and 16º</span>
6 0
3 years ago
Find the with of a triangle as a 15 cm high in a hypogynous of a 19 cm​
Inessa05 [86]

Answer:

This other side of the triangle is equal to about 11.7 cm

Step-by-step explanation:

In order to find out the third side of the triangle we will just use the Pythagoras Theorem.

c^{2} =a^{2} + b^{2}

Since we know the hypotenuse and we know one of the legs, in order to find the second leg we just substitute the values and solve the equation and so we get...

c^{2} =a^{2} + b^{2}\\19^{2} = 15^{2} + b^{2}\\361 = 225 + b^{2} \\

b^{2} = 361 - 225\\b^{2} = 136\\b = \sqrt{136} \\

And so b ≈ 11.66190

8 0
2 years ago
Explain how you used the bar model and exercise to to solve the problem
MariettaO [177]
You need to show us the bar model
8 0
3 years ago
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