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MAVERICK [17]
3 years ago
11

Solve the inequality. Graph the solution. 0 < −12t

Mathematics
1 answer:
frez [133]3 years ago
8 0

Answer:

t<0 or (-∞,0)

Step-by-step explanation:

i think i might be wrong maybe

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Write the given differential equation in the form L(y) = g(x), where L is a linear differential operator with constant coefficie
melamori03 [73]

Answer:

The complete solution is

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

Step-by-step explanation:

Given differential equation is

3y"- 8y' - 3y =4

The trial solution is

y = e^{mx}

Differentiating with respect to x

y'= me^{mx}

Again differentiating with respect to x

y''= m ^2 e^{mx}

Putting the value of y, y' and y'' in left side of the differential equation

3m^2e^{mx}-8m e^{mx}- 3e^{mx}=0

\Rightarrow 3m^2-8m-3=0

The auxiliary equation is

3m^2-8m-3=0

\Rightarrow 3m^2 -9m+m-3m=0

\Rightarrow 3m(m-3)+1(m-3)=0

\Rightarrow (3m+1)(m-3)=0

\Rightarrow m = 3, -\frac13

The complementary function is

y= Ae^{3x}+Be^{-\frac13 x}

y''= D², y' = D

The given differential equation is

(3D²-8D-3D)y =4

⇒(3D+1)(D-3)y =4

Since the linear operation is

L(D) ≡ (3D+1)(D-3)    

For particular integral

y_p=\frac 1{(3D+1)(D-3)} .4

    =4.\frac 1{(3D+1)(D-3)} .e^{0.x}    [since e^{0.x}=1]

   =4\frac{1}{(3.0+1)(0-3)}      [ replace D by 0 , since L(0)≠0]

   =-\frac43

The complete solution is

y= C.F+P.I

\therefore y= Ae^{3x}+Be^{-\frac13 x}-\frac43

4 0
3 years ago
Please answer this question
Alina [70]

Answer:

__

12 x 4 x 7 + 1

__

Step-by-step explanation:

The biggest number can be made by multiplying all the numbers. However, since one of these numbers is 1, multiplying 1 by all those others won’t do anything. So to get the biggest number you would multiply 12 by 4 by 7 and add 1.

3 0
3 years ago
A process produces batches of a chemical whose impurity concentrations follow a normal distribution with a variance of175. A ran
Tom [10]

Answer:

the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)

Step-by-step explanation:

since the variance  S² of the batch follows a normal distribution , then for a sample n of  20 distributions , then the random variable Z:

Z= S²*(n-1)/σ²

follows a χ² ( chi-squared) distribution with (n-1) degrees of freedom

since

S² > 3.10 , σ²= 1.75 , n= 20

thus

Z > 33.65

then from χ² distribution tables:

P(Z > 33.65) = 0.02020

therefore the probability that the sample variance exceeds 3.10 is 0.02020 ( 2,02%)

8 0
4 years ago
Read 2 more answers
Timed test please help. Can someone please help me explain how you graph the circle from the equation below and how you find the
ryzh [129]
Well, you have the radius and the center already. So all you have to do is graph the center point, then count from that center point out 5 units, then draw the circle.
5 0
3 years ago
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|-5| – 45 ÷ 3 <br> Solve please.
IceJOKER [234]
The answer would be 13.3333333 or just 13.33
3 0
3 years ago
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