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2 years ago

Solve the inequality. Graph the solution. 0 < −12t

Mathematics

1 answer:

frez [133]2 years ago

8 0

Answer:

t<0 or (-∞,0)

Step-by-step explanation:

i think i might be wrong maybe

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A circle has a radius of 98 units and is centered at (5.9,6.7) write the equation of the circle

Hoochie [10]

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

radius = √98

center = (5.9,6.7)

equation of the circle = ?

Step 02:

Equation of the circle

(x - a) ² + (y - b) ² = r ²

(a , b) = center

(x - 5.9) ² + (y - 6.7) ² = (√98) ²

(x - 5.9) ² + (y - 6.7) ² = 98

The answer is:

(x - 5.9) ² + (y - 6.7) ² = 98

6 0

9 months ago

W+w+w+w+w+15-7 I got this wrong on a math question. I did 5w+8 = 13w

Aleonysh [2.5K]

$w+w+w+w+w+15-7=\underbrace{w+w+w+w+w}_5+(15-7)\\\\=5w+8-\text{finish}\\\\\text{You can not add 5w and 8. These are different monomials.}$

Example:

5w - five apples

8 - eight strawberries

5w + 8 = (five apples) + (eight strawberries) = 13 of what?

You can add only numbers of the same fruits.

4 0

3 years ago

Read 2 more answers

Y=x^2+bx+c;(-2,3)

Maksim231197 [3]

<h3>Answer: b = 4 and c = 7.</h3>

===============================================

Explanation:

Comparing y = x^2+bx+c to y = ax^2+bx+c, we see that a = 1.

The vertex given is (-2,3). In general, the vertex is (h,k). So h = -2 and k = 3.

Plug those three values into the vertex form below

y = a(x-h)^2 + k

y = 1(x-(-2))^2 + 3

y = (x+2)^2 + 3

Then expand everything out and simplify

y = x^2+4x+4 + 3

y = x^2+4x+7

We see that b = 4 and c = 7.

8 0

2 years ago

Basic Computation: Find Probabilities In Problems 5-14, assume that x has a normal distribution with the specified mean and stan

Ulleksa [173]

Answer:

the answer is below

Step-by-step explanation:

The z score is used to calculate by how many standard deviations the raw score is above or below the mean. The z score is given as:

$z=\frac{x-\mu}{\sigma}\\\\\mu=mean,\sigma=standard\ deviation$

1) For x = 3

$z=\frac{x-\mu}{\sigma}=\frac{3-4}{2}=-0.5$

For x = 6

$z=\frac{x-\mu}{\sigma}=\frac{6-4}{2}=1$

P(3 ≤ x ≤ 6) = P(-0.5 ≤ z ≤ 1) = P(z < 1) - P(z < -0.5) = 0.8413 - 0.3085 = 0.5328

2) For x = 50

$z=\frac{x-\mu}{\sigma}=\frac{50-40}{15}=0.67$

For x = 70

$z=\frac{x-\mu}{\sigma}=\frac{70-40}{15}=2$

P(50 ≤ x ≤ 70) = P(0.67 ≤ z ≤ 2) = P(z < 2) - P(z < 0.67) = 0.9772 - 0.7486 = 0.2286

3) For x = 8

$z=\frac{x-\mu}{\sigma}=\frac{8-15}{3.2}=-2.19$

For x = 12

$z=\frac{x-\mu}{\sigma}=\frac{12-15}{3.2}=-0.94$

P(8 ≤ x ≤ 12) = P(-2.19 ≤ z ≤ -0.94) = P(z < -0.94) - P(z < -2.19) = 0.1736 - 0.0143 = 0.1593

4) For x = 30

$z=\frac{x-\mu}{\sigma}=\frac{30-20}{3.4}=2.94$

P(x ≥ 30) = P(z ≥ 2.94) = 1 - P(z < 2.94) = 1 - 0.9984 = 0.0016

5) x = 90

$z=\frac{x-\mu}{\sigma}=\frac{90-100}{15}=-0.67$

P(x ≥ 90) = P(z ≥ -0.67) = 1 - P(z < -0.67) = 1 - 0.2514 = 0.7486

6) For x = 10

$z=\frac{x-\mu}{\sigma}=\frac{10-15}{4}=-1.25$

For x = 20

$z=\frac{x-\mu}{\sigma}=\frac{20-15}{4}=1.25$

P(10 ≤ x ≤ 20) = P(-1.25 ≤ z ≤ 1.25) = P(z < 1.25) - P(z < -1.25) = 0.8944 - 0.1056 = 0.7888

7) For x = 7

$z=\frac{x-\mu}{\sigma}=\frac{7-5}{1.2}=1.67$

For x = 9

$z=\frac{x-\mu}{\sigma}=\frac{9-5}{1.2}=3.33$

P(7 ≤ x ≤ 9) = P(1.67 ≤ z ≤ 3.33) = P(z < 3.33) - P(z < 1.67) = 0.9996 - 0.9525 = 0.0471

8) For x = 40

$z=\frac{x-\mu}{\sigma}=\frac{40-50}{15}=-0.67$

For x = 47

$z=\frac{x-\mu}{\sigma}=\frac{47-50}{15}=-0.2$

P(40 ≤ x ≤ 47) = P(-0.67 ≤ z ≤ -0.2) = P(z < -0.2) - P(z < -0.67) = 0.4207 - 0.2514 = 0.1693

9) x = 120

$z=\frac{x-\mu}{\sigma}=\frac{120-10}{15}=7.33$

P(x ≥ 120) = P(z ≥ 7.33) = 1 - P(z < 7.33) = 1 - 0.9999 = 0.001

10) x = 2

$z=\frac{x-\mu}{\sigma}=\frac{2-3}{0.25}=-4$

P(x ≥ 2) = P(z ≥ -4) = 1 - P(z < -4) = 1 - 0.0001 = 0.999

3 0

2 years ago

Given that f (x)=x^3−4x and g ( x)=-2x-4, find the zeros. I WILL CALL THE BRAINLEST

sergejj [24]

Answer:

+/-2, -2

Step-by-step explanation:

x^3 = 4x ==> x^2 = 4 ==> x = +/-2

-2x-4 ==>0, -2x=4 ==> x =-2

4 0

3 years ago