The answer is 414,040. After you add
1. x=-2
2. y=-4x+1
3. not sure
Given :
A function , x = 2cos t -3sin t .....equation 1.
A differential equation , x'' + x = 0 .....equation 2.
To Find :
Whether the given function is a solution to the given differential equation.
Solution :
First derivative of x :

Now , second derivative :

( Note : derivative of sin t is cos t and cos t is -sin t )
Putting value of x'' and x in equation 2 , we get :
=(-2cos t + 3sin t ) + ( 2cos t -3sin t )
= 0
So , x'' and x satisfy equation 2.
Therefore , x function is a solution of given differential equation .
Hence , this is the required solution .
Answer:
The answer is C. Lila made an error in Step 3 when she did not use the x- and y-coordinates from the same ordered pair.
Hope this helps!
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