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EastWind [94]
2 years ago
15

Was is 9 Divided 3103

Mathematics
2 answers:
Dominik [7]2 years ago
5 0

Answer:

0.003 but if you just put that in backwards, 345.

Step-by-step explanation:

Alik [6]2 years ago
4 0

Answer:

344\\9*344=3096\\3103-3096=7\\\\344\\Remainder = 7

↓ Step Breakdown ↓

How I got 344 was I asked myself, "How many times does 9 go into 3103?"

To the 1st digit manner, 9 goes into 31(03) 3 times.

Subtract.

Result is 4. Drop the 0 from the tens place to match up.

9 goes into 4(0) 4 times.

Subtract.

The result is 4. Drop the 3 from the ones place.

9 goes into 4(3) 4 times.

Final subtraction.

The final result is 7.

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borishaifa [10]
<h3>Answer:</h3>

F (3x, 3y)

<h3>Explanation:</h3>

Dilation about the origin multiplies each coordinate by the dilation factor. For some coordinates (x, y), dilation by a factor of 3 means the new coordinates are ...

... 3×(x, y) = (3x, 3y)

_____

<em>Comment on the problem</em>

The way the problem is worded, you expect an answer choice that will be specific to the coordinates of point A. There are none.

Instead, the answer choices are generic, corresponding to dilation of a point (x, y) by a factor of 3, translation up and to the right by 3, dilation by a factor of 1/3, and translation down and to the left by 3.

8 0
3 years ago
Pleas help me solve and can you show me how you solved it
matrenka [14]

Answer: K=2

Step-by-step explanation:

-8k+6=-10k+10

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3 0
3 years ago
Read 2 more answers
In a horse race with 5 horses, you make a bet by predicting the ranking of all 5 horses. Suppose you place your bet at random. W
lapo4ka [179]

Answer:

P( top two horses are predicted incorrectly in incorrect order)

= \frac{1}{2}

Step-by-step explanation:

In the horse race the outcome can be predicted in 5! = 120 ways.

Now suppose the top two horses were predicted incorrectly in incorrect order. Now, the  top horse can be predicted incorrectly in 4 ways.

Suppose the top horse was predicted to be in k-th position where k = 2, 3 ,4,5

so the second horse can be predicted to be in place from 1 to (k - 1)

So, the top two horses can be predicted  incorrectly in incorrect order

in \sum_{k =2}^{5}(k - 1) = 10 ways  

and for each prediction of the two the remaining horses may be predicted in 3! = 6 ways.

Hence ,

P( top two horses are predicted incorrectly in incorrect order)

= \frac{6 \times 10}{120}

=\frac{1}{2}

 

8 0
3 years ago
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2nd one
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1 year ago
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Neko [114]

Answer:

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Step-by-step explanation:

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