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Damm [24]
2 years ago
14

The term 'aspect ratio' is a specification of ...

Computers and Technology
1 answer:
STatiana [176]2 years ago
5 0

Answer:

I believe the correct aswer is D. Monitors

Explanation:

The aspect ratio of a display device is the proportional relationship between the width and the height of the display. It is expressed as two numbers separated by a colon (x:y), where x corresponds to the width and y to the height. Common aspect ratios for displays, past and present, include 5:4, 4:3, 16:10 and 16:9.

I hope that help!

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Range paramters - for loop<br> question in picture
Luba_88 [7]

Answer:

start,stop,step_size

Explanation:

Starting at 5 to for loop will count backward by 1 (hence the step_size being -1) until it reaches 0 (stop).

4 0
2 years ago
A network administrator manages a network with 75 servers. At least twenty of those servers are approaching end of life but the
Gekata [30.6K]

Answer:

Virtual servers

Explanation:

4 0
3 years ago
Which of the following is not an example of technological progress? A: new scientific knowledge that has practical applications
kirill115 [55]
Why isn't there an option [B]? :p

Ah, nevermind. I believe the answer is [C], anyway. Simply building new roads and adding to existing infrastructures cannot really be counted as a "technological improvement". Nothing is technologically improving.
3 0
4 years ago
Read 2 more answers
An attribute that can have more than one value for each entity instance is referred to as:
ss7ja [257]

Answer:

D) a multivalued attribute

Explanation:

A multivalued attribute  can have more than one value associated with the entity key.

6 0
3 years ago
(a) Show how to use (the Boolean formula satisfiability program) satisfiable num (and substitute) to find a satisfying assignmen
tia_tia [17]

Answer:

Check the explanation

Explanation:

(a)

# We need to try all options(TRUE/FALSE) of all the Variables

# to find the correct arrangement.

permutations <- permutate(0,1,n) [Find all permutions O(2^n)]

for permutation in permutations:

for X in variables:

if(permutation[i] == 1)

substitute(H,X,true)

else

substitute(H,X,false)

if(satisfiable(H)) return permutation

increment i

6 0
3 years ago
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