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4 years ago

Linux is

Computers and Technology

1 answer:

Lemur [1.5K]4 years ago

7 0

Answer:

Option C is the correct answer for the above question.

Explanation:

Open-source software is a concept which means that a user can see the software source code and can modify the software for its personal use if it is open-source software.

Linux is also the open-source software and free of cost available in the market. hence the option c is correct while the other is not because--

Option A states that Linux is only for end users but Linux is for server, client and for the developer.
Option B states that it is designed for a specific purpose but it is for any type of work.
Option D states that Linux is for numeric data only but it uses for all types of data.

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What type of tests is suitable for automated testing?

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3 years ago

What is commodity? explain

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3 years ago

Assignment 8: Personal Organizer (in edhesive or python please)

serg [7]

Answer:

eventName = []

eventMonth = []

eventDay = []

eventYear = []

def addEvent():

userEventName = input("Enter event name: ")

userEventMonth = int(input("Enter event month (1-12): "))

userEventDay = int(input("Enter event day(1-31): "))

userEventYear = int(input("Enter event year (Ex:2020): "))

userEventMonth = validateMonth(userEventMonth)

userEventDay = validateDay(userEventMonth,userEventDay,userEventYear)

eventName.append(userEventName)

eventMonth.append(userEventMonth)

eventDay.append(userEventDay)

eventYear.append(userEventYear)

def validateMonth(month):

if month >= 1 and month <= 12:

return month

else:

return 1

def validateDay(month,day,year):

# invalid days

if day < 1 or day > 31 :

return 1

# if the month is february

if month == 2:

isleap = False

if year%4 == 0:

if year%100 == 0:

if year%400 == 0:

isleap = True

else:

isleap = True

# if the year is leap

if isleap:

if day < 30:

return day

else:

return 1

else:

if day < 29:

return day

else:

return 1

# month with 31 days

if month in [1,3,5,7,8,10,12]:

return day

# month with 30 days

if month in [4,6,9,11] and day < 31:

return day

else:

return 1

def printEvents():

print("****** LIST OF EVENTS *********")

months = ['January', 'February', 'March', 'April', 'May', 'June', 'July',

'August', 'September', 'October', 'November', 'December']

for index in range(len(eventName)):

print(eventName[index])

print("Date: "+months[eventMonth[index] -1]+ " " + str(eventDay[index]) + ", " + str(eventYear[index]))

def printEventsForMonth(month):

months = ['January', 'February', 'March', 'April', 'May', 'June', 'July',

'August', 'September', 'October', 'November', 'December']

print("****** EVENTS IN " + months[month -1] + " *********")

for index in range(len(eventName)):

if eventMonth[index] == month:

print(eventName[index])

print("Date: "+months[eventMonth[index] -1]+ " " + str(eventDay[index]) + ", " + str(eventYear[index]))

userChoice = "yes"

while userChoice.upper() != "NO":

addEvent()

userChoice = input("Do you want to enter another event? NO to stop: ")

printEvents()

Explanation:

hope this saved somebody from a mental breakdown :)

3 0

3 years ago

Read 2 more answers

Write the definition of a function named quadratic that receives three double parameters a, b, c. If the value of a is 0 then th

VMariaS [17]

Answer:

#include <iostream>

#include <cmath>

using namespace std;

//initialize function quadratic

void quadratic(double, double, double);

int main() {

//declare double variables a, b and c

double a,b,c;

//take input from user

cin>>a>>b>>c;

//call function quadratic

quadratic(a,b,c);

return 0;

}

void quadratic(double a, double b, double c){

double root,n;

//check if variable a is equal to zero

if(a==0){

cout<<"no solution for a=0"<<endl;

return;

}

//check if b squared - 4ac is less than zero

else

if(((b*b)-(4*a*c))<0){

cout<<"no real solutions"<<endl;

return;

}

//print the largest root if the above conditions are not satisfied

else{

n=((b*b)-(4*a*c));

root=(-b + sqrt(n)) / (2*a);

cout<<"Largest root is:"<<root<<endl;

}

return ;

}

Explanation:

Read three double variables a, b and c from the user and pass it to the function quadratic. Check if the value of variable a is equal to zero. If true, print "no solution for a=0". If this condition is false, check if b squared - 4ac is less than zero. If true, print "no real solutions". If this condition is also false, calculate the largest solution using the following formula:

largest root = (-b + square root of (b squared - 4ac)) / (2*a)

Input 1:

2 5 3

Output 2:

Largest root is:-1

Input 2:

5 6 1

Output 2:

Largest root is:-0.2

5 0

4 years ago