Answer: You can add neutral solutions with a pH of 7, like water. Water will dissolve the alkaline/acidic pH to near 7 and 8, which are safe to drink.
Hope this helps you!
Answer:
See
Explanation:
Given:
Brown allele (B) is dominant over the white allele (b).
It will be assumed that the alleles are not related to the X and Y chromosomes.
See attached diagram for details of the general case (for both homo-zygous and hetero-zygous parents)
For both parents hetero-zygous,
P1:
Genotype: Bb (100%)
Phenotype: brown (100%)
F1:
Genotypes : BB, Bb, bB and bb in equal proportions, i.e.
BB (25%), Bb (50%), bb (25%)
Phenotypes: 75% brown (from BB and Bb), 25% white (from bb)
Answer:
The amount of ⛅ sunlight .
Explanation:
PLEASE MARK AS BRAINLIEST
Answer: 1/4
Explanation:
Firstly, in order for both parents to be type A and have children with type o blood, their blood types must both be Ao. Since o is a recessive blood type, a punnett square shows there is a 25% chance any child of theirs will have type o blood. If neither parent is color blind and they have a son who is, it implies that the mother is a carrier of colorblindness and has the genotype XᴮXᵇ. If you do a punnett square of the not colorblind father (XᴮY) and the mother, it shows that a daughter would have a 0% chance of being colorblind. Therefore colorblindess is irrelevent, since there is no possibility of the daughter not having normal color vision. In conclusion, there's a 25% chance she will have type o blood and not be colorblind, since the other 75% chance would be having type A blood and not being colorblind.
Answer:
C.
It is able to regulate the flow of the calcium oxide and water into the food to make it warm.
Explanation: