Answer:
c, the third answer
Step-by-step explanation:
Answer:
the capacity of the airplane be 200 passengers
Step-by-step explanation:
According to the question, the data provided is as follows
Number of passengers in an airplane = 180
Capacity = ![\frac{9}{10}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B10%7D)
Based on the above information
Let us assume the capacity of the airplane be x
So the equation would be
![\frac{9}{10} \times x = 180\\\\\\x = \frac{1,800}{9}](https://tex.z-dn.net/?f=%5Cfrac%7B9%7D%7B10%7D%20%5Ctimes%20x%20%3D%20180%5C%5C%5C%5C%5C%5Cx%20%3D%20%5Cfrac%7B1%2C800%7D%7B9%7D)
So x = 200
Therefore the capacity of the airplane be 200 passengers
We simply applied the above equation so that the capacity of the airplane could come
Answer:
a) 513775.5 m^3 ≈ 51.38 * 10^4 m^3
b) 256887.75 m^3 ≈ 25.69 * 10^4 m^3
Step-by-step explanation:
Given data :
Depth of pond = 2m
flow in the stream = 20 cfs = 4.8931 * 10^4 m^3/day
settling rate = 0.2 m/day
rate constant ( k )= 0.2 / 2 = 0.1 / day
steady-state removal of the solids required = 65%
<u>A) determine size of a single CSTR to achieve 65%</u>
First determine the time required to achieve this using the relation below
C =
∴ t = ![\frac{-1}{k}* ln( 1 - 0.65 )](https://tex.z-dn.net/?f=%5Cfrac%7B-1%7D%7Bk%7D%2A%20ln%28%201%20-%200.65%20%29)
= ( -1 / 0.1 ) * (- 1.05 ) = 10.5 day
The size of a single CSTR required = ( 4.8931*10^4 ) * (10.5 ) = 513775.5 m^3
<u>B) determine the sizes of a pair of identical CSTRs in series needed to achieve the desired removal</u>
sizes of a pair = 513775.5 / 2 = 256887.75 m^3
6 divided by -0.5 is -12. So that means you could multiply -0.5 and -12 to get 6. Hope this helps!
Answer with Step-by-step explanation:
We are given that
![g(x)=(x^2-3x-10)(x^2+2x^2-5x+4)](https://tex.z-dn.net/?f=g%28x%29%3D%28x%5E2-3x-10%29%28x%5E2%2B2x%5E2-5x%2B4%29)
x=-1
Using property of limit
![\lim_{x\rightarrow -1}g(x)=\lim_{x\rightarrow -1}(x^2-3x-10)(3x^2-5x+4)](https://tex.z-dn.net/?f=%5Clim_%7Bx%5Crightarrow%20-1%7Dg%28x%29%3D%5Clim_%7Bx%5Crightarrow%20-1%7D%28x%5E2-3x-10%29%283x%5E2-5x%2B4%29)
=![(1+3-10)(3+5+4)](https://tex.z-dn.net/?f=%281%2B3-10%29%283%2B5%2B4%29)
=![(-6)(12)](https://tex.z-dn.net/?f=%28-6%29%2812%29)
=![-72](https://tex.z-dn.net/?f=-72)
![g(-1)=(1+3-10)(1+2+5+4)](https://tex.z-dn.net/?f=g%28-1%29%3D%281%2B3-10%29%281%2B2%2B5%2B4%29)
![g(-1)=(-6)(12)=-72](https://tex.z-dn.net/?f=g%28-1%29%3D%28-6%29%2812%29%3D-72)
![\lim_{x\rightarrow -1}g(x)=g(-1)](https://tex.z-dn.net/?f=%5Clim_%7Bx%5Crightarrow%20-1%7Dg%28x%29%3Dg%28-1%29)
Hence, the function is continuous at x=-1