Answer:
The area of triangle ACE before dilation is: 30 square inches
Step-by-step explanation:
We know that when an object is dilated by a scale factor, it gets reduced, stretched, or remains the same, depending upon the value of the scale factor.
- If the scale factor > 1, the image is enlarged
- If the scale factor is between 0 and 1, it gets shrunk
- If the scale factor = 1, the object and the image are congruent
The length of the image can be determined by multiplying the length of the original point by a certain scale factor.
Given that after triangle ACE is dilated by a factor of 6, it has an area of 180 square inches.
Thus, it means the dilated area is 6 times the area before dilation.
Let x be the pre-dilation area
As the dilated area is 6 times the area before dilation, so
6x = 180
divide both sides by 6
6x/6 = 180/6
x = 30 square inches.
Therefore, the area of triangle ACE before dilation is: 30 square inches
Answer:
a
Step-by-step explanation:
3/15 simplifies to 1/5
Answer:
(a) See attachment for tree diagram
(b) 24 possible outcomes
Step-by-step explanation:
Given
Solving (a): A possibility tree
If urn 1 is selected, the following selection exists:
![B_1 \to [R_1, R_2, R_3]; R_1 \to [B_1, R_2, R_3]; R_2 \to [B_1, R_1, R_3]; R_3 \to [B_1, R_1, R_2]](https://tex.z-dn.net/?f=B_1%20%5Cto%20%5BR_1%2C%20R_2%2C%20R_3%5D%3B%20R_1%20%5Cto%20%5BB_1%2C%20R_2%2C%20R_3%5D%3B%20R_2%20%5Cto%20%5BB_1%2C%20R_1%2C%20R_3%5D%3B%20R_3%20%5Cto%20%5BB_1%2C%20R_1%2C%20R_2%5D)
If urn 2 is selected, the following selection exists:
![B_2 \to [B_3, R_4, R_5]; B_3 \to [B_2, R_4, R_5]; R_4 \to [B_2, B_3, R_5]; R_5 \to [B_2, B_3, R_4]](https://tex.z-dn.net/?f=B_2%20%5Cto%20%5BB_3%2C%20R_4%2C%20R_5%5D%3B%20B_3%20%5Cto%20%5BB_2%2C%20R_4%2C%20R_5%5D%3B%20R_4%20%5Cto%20%5BB_2%2C%20B_3%2C%20R_5%5D%3B%20R_5%20%5Cto%20%5BB_2%2C%20B_3%2C%20R_4%5D)
<em>See attachment for possibility tree</em>
Solving (b): The total number of outcome
<u>For urn 1</u>
There are 4 balls in urn 1
Each of the balls has 3 subsets. i.e.
So, the selection is:
<u>For urn 2</u>
There are 4 balls in urn 2
Each of the balls has 3 subsets. i.e.
So, the selection is:
Total number of outcomes is:
Answer:
6/9 and 8/12 is the answer
Step-by-step explanation:
simplify both ratios
6/9 divide by 3 to =2/3
8/12 divide by 4 to =2/3
Answer:
v=5.42m/s
Step-by-Step Explanation:
We can use conservation of energy to solve this
mgh=1/2mv^2
2gh=v^2
v=sqrt(2gh)
v=sqrt[2*9.8m/s^2*(6.5-5)]
v=5.42m/s
