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3 years ago

Recursive formula for the sequence 9,11,13,15

Mathematics

1 answer:

nasty-shy [4]3 years ago

4 0

Answer:

idkmbb

Stepidk-by-step explanation:

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Simplify each expression.<br> 1) 6(1 - 10p)- 7

Y_Kistochka [10]

Answer:

-60p - 1

Step-by-step explanation:

Distribute the parenthesis then add like terms together.

Step 1: Distribute

6 -60p - 7

Step 2: Combine like terms

-60p - 1

4 0

3 years ago

Read 2 more answers

A pair of parallel lines is cut by a transversal, as shown (see figure):

Anestetic [448]

The answer
let p' be the corresponding angle of the angle p (that is because of the prallelism and the transversal, look the image)
but p' and p are correspondant angles implies p'=p,
looking at the figure, p' and q are opposite angles
so q=p' and p'=p implies q=p
the answer is
<span>p = q</span>

4 0

3 years ago

Read 2 more answers

Evaluate the following integral using trigonometric substitution

serg [7]

Answer:

The result of the integral is:

$\arcsin{(\frac{x}{3})} + C$

Step-by-step explanation:

We are given the following integral:

$\int \frac{dx}{\sqrt{9-x^2}}$

Trigonometric substitution:

We have the term in the following format: $a^2 - x^2$ , in which a = 3.

In this case, the substitution is given by:

$x = a\sin{\theta}$

$dx = a\cos{\theta}d\theta$

In this question:

$a = 3$

$x = 3\sin{\theta}$

$dx = 3\cos{\theta}d\theta$

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}$

We have the following trigonometric identity:

$\sin^{2}{\theta} + \cos^{2}{\theta} = 1$

$1 - \sin^{2}{\theta} = \cos^{2}{\theta}$

Replacing into the integral:

$\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C$