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astraxan [27]
2 years ago
15

I need help on this problem

Mathematics
1 answer:
Tatiana [17]2 years ago
8 0

Answer:

D

Step-by-step explanation:

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Factor this problem ?<br> 125 +27y^3
koban [17]

Answer:

(5 + 3y)(25 - 15y + 9y²)

Step-by-step explanation:

This is a sum of cubes and factors in general as

a³ + b³ = (a + b)(a² - ab + b²), thus

125 + 27y³

= 5³ + (3y)³ with a = 5 and b = 3y

= (5 + 3y)(5² - 5(3y) + (3y)² )

= (5 + 3y)(25 - 15y + 9y²)

6 0
3 years ago
The price of a television decreased from $1000.00 to $800.00. What was the percent of decrease? a. 2% b. 18% c. 20% d. 25%
sweet-ann [11.9K]
If we divide 800/1000, we get .8 This means The price of $800 is only 80% of  $1000. Furthermore, this also means that there was a decrease in price of 20%. The answer is C.
4 0
4 years ago
Point A (-6, 2) and B (4, k) lie on a line that has a slope of 3/5 Determine the value of K
____ [38]

Answer:

k=8

Step-by-step explanation:

We can solve using the slope formula

m= (y2-y1)/(x2-x1)

3/5 = (k-2)/(4- -6)

3/5 = (k-2)/(4+6)

3/5 = (k-2)/10

Multiply each side by 10

10*3/5 = (k-2)/10 *10

6 = k-2

Add 2 to each side

6+2 = k-2+2

8 = k

8 0
3 years ago
Answer this question if you don't smell like moldy pizza. What is 2 plus 78 divided by 0
olchik [2.2K]

Answer:

infinity

Step-by-step explanation:

3 0
3 years ago
Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re
fiasKO [112]

Answer: R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts 38^{\circ} angle to each other

The resultant of the two forces is given by

\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}

Insert the values

\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb

Resultant makes an angle of

\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}

So, the resultant makes an angle of 22.57^{\circ} with 9 lb force

Angle made with 13 lb force is 38^{\circ}-22.57^{\circ}=15.43^{\circ}

7 0
3 years ago
Read 2 more answers
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