D. 36 cm that’s how I got my answer
Answer
Given,
Period of the Pendulum, T= 1 s
acceleration due to gravity, g = 9.8 m/s²
Length of Bob = 0.2482 m
Loss of time in the clock = 1.5 minutes/ day
Loss of time in 1 oscillation
= 
= 0.001042
Hence, time period, T = 1 + 0.001042
T = 1.001042 s
a) Using Time period of oscillation formula



Free fall acceleration at the clock location = 9.77 m/s²
b) Length of pendulum bob to keep it perfect time



Hence, Length of pendulum bob is equal to 0.2475 m.
Answer:
<em>(8.21, -20.79)</em>
Step-by-step explanation:
Given the simultaneous equation;

From 2;
a = 29 + b ....3
Substitute 3 into 1;

Factorize
b = -18±√18²-4(-58)/2
b = -18±√324+232/2
b = -18±√556/2
b = -18±23.58/2
b = -18-23.58/2 and -18+23.58/2
b = -41.58/2 and 5.58/2
b = -20.79 and 2.79
Since a = 29 + b
when b = -20.79
a = 29 - 20.79
a = 8.21
<em>Hence the solution to the system of equation is (8.21, -20.79)</em>
Answer:
Drink A
Step-by-step explanation:
Let's find the amount of sugar in each drink in every 35 ounces. (since 35 is the lowest common multiple of 5 and 7)
<u>Drink</u><u> </u><u>A</u>
5 fluid ounces --- 11g of sugar
35 fluid ounces --- 11 ×7= 77g of sugar
<u>Drink</u><u> </u><u>B</u>
7 fluid ounces --- 10g of sugar
35 fluid ounces --- 10 ×5= 50g of sugar
Since drink A has more sugar in every 35 ounces than drink B, drink A is sweeter.
The answer is 5 and 2/5. Hopefully it is correct!