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Scrat [10]
3 years ago
7

I am terrible at math, so i might need some help with this

Mathematics
1 answer:
valentina_108 [34]3 years ago
7 0

Answer:

A=143

Step-by-step explanation:

It is addition and subtraction here, so you will add the money into the bank account. If you also need B and C, it is -86 for B and 86 for C respectively

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4vir4ik [10]
1864 is the answer for your question
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Mathematical model in real life
matrenka [14]
Well, one example would be how much space is in a cardboard box, to ship something to a friend or relative. 
We know the three measurements:
L = Length, W = Width, and H = Height.

And the formula for a volume of a cube is:
V = L*W*H

So say that:
L = 6 , W = 10 Feet, and H = 3 Feet.
By using the formula above we get the equation: V = 6*10*3
And that equals: 180 Feet.
So the volume of the box, or the space you have to send something is 180 square feet. 

Does this help?

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6 0
3 years ago
To find the quotient of 4 ÷ <br> 1<br> 8<br> , count the number of
Ivanshal [37]

Answer:

the answer is 32

Step-by-step explanation:

6 0
2 years ago
Save me the headache
maxonik [38]

(9\sin2x+9\cos2x)^2=81

Taking the square root of both sides gives two possible cases,

9\sin2x+9\cos2x=9\implies\sin2x+\cos2x=1

or

9\sin2x+9\cos2x=-9\implies\sin2x+\cos2x=-1

Recall that

\sin(\alpha\pm\beta)=\sin\alpha\cos\beta\pm\cos\alpha\sin\beta

If \alpha=2x and \beta=\dfrac\pi4, we have

\sin\left(2x+\dfrac\pi4\right)=\dfrac{\sin2x+\cos2x}{\sqrt2}

so in the equations above, we can write

\sin2x+\cos2x=\sqrt2\sin\left(2x+\dfrac\pi4\right)=\pm1

Then in the first case,

\sqrt2\sin\left(2x+\dfrac\pi4\right)=1\implies\sin\left(2x+\dfrac\pi4\right)=\dfrac1{\sqrt2}

\implies2x+\dfrac\pi4=\dfrac\pi4+2n\pi\text{ or }\dfrac{3\pi}4+2n\pi

(where n is any integer)

\implies2x=2n\pi\text{ or }\dfrac\pi2+2n\pi

\implies x=n\pi\text{ or }\dfrac\pi4+n\pi

and in the second,

\sqrt2\sin\left(2x+\dfrac\pi4\right)=-1\implies\sin\left(2x+\dfrac\pi4\right)=-\dfrac1{\sqrt2}

\implies2x+\dfrac\pi4=-\dfrac\pi4+2n\pi\text{ or }-\dfrac{3\pi}4+2n\pi

\implies2x=-\dfrac\pi2+2n\pi\text{ or }-\pi+2n\pi

\implies x=-\dfrac\pi4+n\pi\text{ or }-\dfrac\pi2+n\pi

Then the solutions that fall in the interval [0,2\pi) are

x=0,\dfrac\pi4,\dfrac\pi2,\dfrac{3\pi}4,\pi,\dfrac{5\pi}4,\dfrac{3\pi}2,\dfrac{7\pi}4

5 0
3 years ago
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I need doing this please ?
Alex17521 [72]

Answer:

i do not know

Step-by-step explanation:

sorry

3 0
2 years ago
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