Hello,
Let's x² the square number
and 3*y the multiple of 3.

2 solutions : for (x,y) as integers : (-6,18) and (6,18)
but one solution for (x²,3y) as integers :<u> (36,54) </u>
Answer:
Since b^2 -4ac = 256 we have 2 real distinct root roots
Step-by-step explanation:
4x^2+12x=7
We need to subtract 7 to get it in the proper form
4x^2+12x-7=7-7
4x^2+12x-7=0
The discriminant is b^2 -4ac
when the equation is ax^2 +bx+c
so a =4 b=12 and c=-7
(12)^2 - 4(4)(-7)
144 +112
256
If b^2 -4ac > 0 we have 2 real distinct roots
If b^2 -4ac = 0 we have one real root
If b^2 -4ac < 0 we have two complex root
Since b^2 -4ac = 256 we have 2 real distinct root roots
The domain for which the function is defined is given by:
D.
.
<h3>What is the domain of a function?</h3>
The domain of a function is the set that contains all possible input values for the function.
A square root is only defined for non-negative values, hence:
.
.
The intersection of these two domains is
, hence option D is correct.
More can be learned about the domain of a function at brainly.com/question/10891721
#SPJ1
She would make 3.00 dollars
50(10) - 20(10) = (10)(50 - 20)
500 - 200 = (10 * 30)
300 = 300
(10)(50 - 20) = 30(10)
(10 * 30) = 300
300 = 300