All categories

2 years ago

PLEASE SAVE ME FROM THIS PHYSICS QUESTION (WILL MARK BRAINLIEST)

Physics

1 answer:

Mnenie [13.5K]2 years ago

8 0

Answer:

See Below

Explanation:

Mass of child = 21 kg

Mass of bicycle = 5.9 kg

Total mass = 22 + 5.9 = 27.9 kg

Velocity = 4.5 m/s

1) Total momentum of the child and the bike together

= Total mass * Velocity

= 27.9*4.5

= 125.55 kg m per second

2) Momentum of the child

= Mass of child*Velocity

= 21*5.9

= 123.9 kg m per second

3) Momentum of the bike

= Mass of bike*Velocity

= 5.9*4.5

= 26.55 kg m per second

You might be interested in

Difference between uniform circular motion and non uniform circular motion

Goryan [66]

Uniform circular motion is the motion in which an object covers equal distance in equal interval of time in a circular path and in non uniform motion object covers equal distance in unequal interval of time in a circular path

6 0

3 years ago

A spherical shell has an outside radius of 2.60 cm and an inside radius of a. The shell wall has uniform thickness and is made o

lbvjy [14]

Answer:

The answer is below

Explanation:

a) The volume of a sphere is:

Volume = (4/3)πr³; where r is the radius of the shell.

Given the outside radius of 2.60 cm and inner radius of a cm, the volume of the spherical shell is:

Volume of spherical shell = $\frac{4}{3} \pi (2.6^3-a^3)$ cm³

But Density = mass / volume; Mass = density * volume.

Therefore, mass of spherical shell = density * volume

mass of spherical shell = $4.70\ g/cm^3$ * $\frac{4}{3} \pi (2.6^3-a^3)$ cm³

Mass of liquid = volume of inner shell * density of liquid

Mass of liquid = $\frac{4}{3} \pi a^3\ cm^3*1.23\ g/cm^3$

Total mass of sphere including contents = mass of spherical shell + mass of liquid

Total mass of sphere including contents (M) = $4.70\ g/cm^3$ * $\frac{4}{3} \pi (2.6^3-a^3)\ cm^3$ + $\frac{4}{3} \pi a^3\ cm^3*1.23\ g/cm^3$ =

Total mass of sphere including contents (M) = (346 - 14.5a³) grams

b) The mass is maximum when the value of a = 0

M = 346 - 14.5a³

M' = 43.5a² = 0

43.5a² = 0

a = 0

4 0

3 years ago

A hydraulic lift consists of two pistons that connect to each other by an incompressible fluid. If one piston has an area of 0.1

hjlf

You have:

A1= 0.15 m²
A2=6.0 m²
F1=130.0 N

To solve this problem you must use the pressure formula, as below:

P1=P2
F1/A1=F2/A2

Then, you have:

m2=A2xF1/A1xg

g=9.81 m/s² (This is the acceleration of gravity)

When you substitute the values in m2=A2xF1/A1xg, you obtain:

m2=(0.60 m² x 130.0 N)/(0.15 m² x 9.81 m/s²)

The answer is:

m2=530 Kg

5 0

4 years ago

Gwar [14]

Answer:

For 1: The correct option is Option C.

For 3: The final velocity of the opponent is 1m/s

Explanation:

During collision, the energy and momentum remains conserved. The equation for the conservation of momentum follows:

$m_1u_1+m_2u_2=m_1v_1+m_2v_2$ ...(1)

where,

$m_1,u_1\text{ and }v_1$ are the mass, initial velocity and final velocity of first object

$m_2,u_2\text{ and }v_2$ are the mass, initial velocity and final velocity of second object

For 1:

We are Given:

$m_1=150g=0.15kg\\u_1=?m/s\\v_1=0.85m/s\\m_2=3500g=3.5kg\\u_2=0m/s\\v_2=0.85m/s$

Putting values in equation 1, we get:

$(0.15\times u_1)+(3.5\times 0)=(3.5+0.15)\times 0.85\\\\u_1=20.683\approx 21m/s$

Hence, the correct answer is Option C.

For 2:

Impulse is defined as the product of force applied on an object and time taken by the object.

Mathematically,

$J=F\times t$

where,

F = force applied on the object

t = time taken

J = impulse on that object

Impulse depends only on the force and time taken by the object and not dependent on the surface which is stopping the object.

Hence, the impulse remains the same.

For 3:

Let the speed in right direction be positive and left direction be negative.

We are Given:

$m_1=240kg\\u_1=0m/s\\v_1=-1m/s\\m_2=80kg\\u_2=-2m/s\\v_2=?m/s$

Putting values in equation 1, we get:

$(240\times 0)+(80\times (-2))=(240\times (-1))+(80\times v_2)\\\\v_2=1m/s$

Hence, the final velocity of the opponent is 1m/s and has moved backwards to its direction of the initial velocity.

4 0

3 years ago

Does Newton’s 1st Law of Motion apply to sports

Ksenya-84 [330]

Answer: Yes indeed it does.

Explanation: Newton's Three Laws of Motion explain how forces create motion in sport. These laws are usually referred to as the Laws of Inertia, Acceleration, and Reaction. maybe brainliest to level up.

5 0

3 years ago