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3 years ago

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A spherical shell has an outside radius of 2.60 cm and an inside radius of a. The shell wall has uniform thickness and is made o

f a material with density 4.70 g/cm3. The space inside the shell is filled with a liquid having a density of 1.23 g/cm3. (a) Find the mass m of the sphere, including its contents, as a function of a. (b) In the answer to part (a), if a is regarded as a variable, for what value of a does m have its maximum possible value

1 answer:

lbvjy [14]3 years ago

4 0

Answer:

The answer is below

Explanation:

a) The volume of a sphere is:

Volume = (4/3)πr³; where r is the radius of the shell.

Given the outside radius of 2.60 cm and inner radius of a cm, the volume of the spherical shell is:

Volume of spherical shell = $\frac{4}{3} \pi (2.6^3-a^3)$ cm³

But Density = mass / volume; Mass = density * volume.

Therefore, mass of spherical shell = density * volume

mass of spherical shell = $4.70\ g/cm^3$ * $\frac{4}{3} \pi (2.6^3-a^3)$ cm³

Mass of liquid = volume of inner shell * density of liquid

Mass of liquid = $\frac{4}{3} \pi a^3\ cm^3*1.23\ g/cm^3$

Total mass of sphere including contents = mass of spherical shell + mass of liquid

Total mass of sphere including contents (M) = $4.70\ g/cm^3$ * $\frac{4}{3} \pi (2.6^3-a^3)\ cm^3$ + $\frac{4}{3} \pi a^3\ cm^3*1.23\ g/cm^3$ =

Total mass of sphere including contents (M) = (346 - 14.5a³) grams

b) The mass is maximum when the value of a = 0

M = 346 - 14.5a³

M' = 43.5a² = 0

43.5a² = 0

a = 0

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Answer:

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Explanation:

From the question we are told that

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4 years ago

Two cars are traveling at the same speed of 27 m/s on a curve thathas a radius of 120 m. Car A has a mass of 1100 kg and car B h

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Answer:

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Explanation:

Normal or centripetal acceleration measures change in speed direction over time. Its expression is given by:

$a_{c} = \frac{v^{2} }{r}$ Formula 1

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$a_{c}$ : Is the normal or centripetal acceleration of the body ( m/s²)

v: It is the magnitude of the tangential velocity of the body at the given point

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∑F = m*a Formula ( 2)

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Data

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Problem development

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$a_{cA} = \frac{(27)^{2} }{120}$

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$a_{cB} = 6.075$ m/s²

We replace data in formula (2) to calculate centripetal force Fc) :

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