A spherical shell has an outside radius of 2.60 cm and an inside radius of a. The shell wall has uniform thickness and is made o
1 answer:
Answer:
The answer is below
Explanation:
a) The volume of a sphere is:
Volume = (4/3)πr³; where r is the radius of the shell.
Given the outside radius of 2.60 cm and inner radius of a cm, the volume of the spherical shell is:
Volume of spherical shell = cm³
But Density = mass / volume; Mass = density * volume.
Therefore, mass of spherical shell = density * volume
mass of spherical shell = *
cm³
Mass of liquid = volume of inner shell * density of liquid
Mass of liquid =
Total mass of sphere including contents = mass of spherical shell + mass of liquid
Total mass of sphere including contents (M) = *
+
=
Total mass of sphere including contents (M) = (346 - 14.5a³) grams
b) The mass is maximum when the value of a = 0
M = 346 - 14.5a³
M' = 43.5a² = 0
43.5a² = 0
a = 0
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Answer:
The second projectile was 1.41 times faster than the first.
Explanation:
In the ballistic pendulum experiment, the speed (v) of the projectile is given by:
<em>where m: is the mass of the projectile, M: is the mass of the pendulum, g: is the gravitational constant and h: is the maximum height of the pendulum. </em>
To know how many times faster was the second projectile than the first, we need to take the ratio for the velocities for the projectiles 2 and 1:
(1)
<em>where m₁ and m₂ are the masses of the projectiles 1 and 2, respectively, and h₁ and h₂ are the maximum height reached by the pendulum by the projectiles 1 and 2, respectively. </em>
Since the projectile 1 has the same mass that the projectile 2, we can simplify equation (1):
Therefore, the second projectile was 1.41 times faster than the first.
I hope it helps you!