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3 years ago

Difference between uniform circular motion and non uniform circular motion

1 answer:

6 0

Uniform circular motion is the motion in which an object covers equal distance in equal interval of time in a circular path and in non uniform motion object covers equal distance in unequal interval of time in a circular path

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A 2.0 m length of wire is made by welding the end of a 120 cm long silver wire to the end of an 80 cm long copper wire. Each pie

Levart [38]

<u>Explanation</u>:

Resistivity of silver wire = $1.47 e-8 ohm meter$

Resistivity of copper wire = $1.72 \mathrm{e}-8 \text { ohm meter }$

Resistance = Resistivity *length/cross sectional area

$R=\rho_{L / A}$

So,

$\begin{aligned}&I=A\left(V / P_{A g} L_{A g}+P_{C u} L C_{U}\right)\\&1=8104 \mathrm{A}\end{aligned}$

For E calculation

For copper

E = resistivity * current density

E = Resistivity * current/area

$E=4.9298 \mathrm{V} / \mathrm{m}$

For silver

$E=4.213 \mathrm{V} / \mathrm{m}$

Potential difference $=E^{*} L$

For silver

Potential difference = $4.213^{*} 1.2=5.055 \mathrm{V}$

For copper

Potential difference = $3.9438 \mathrm{V}$

7 0

3 years ago

The emission of x rays can be described as an inverse photoelectric effect.

timama [110]

Answer:

The potential difference through which an electron accelerates to produce x rays is $1.24\times 10^4\ volts$ .

Explanation:

It is given that,

Wavelength of the x -rays, $\lambda=0.1\ nm=0.1\times 10^{-9}\ m$

The energy of the x- rays is given by :

$E=\dfrac{hc}{\lambda}$

The energy of an electron in terms of potential difference is given by :

$E=eV$

So,

$\dfrac{hc}{\lambda}=eV$

V is the potential difference

e is the charge on electron

$V=\dfrac{hc}{e\lambda}$

$V=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{1.6\times 10^{-19}\times 0.1\times 10^{-9}}$

V = 12431.25 volts

$V=1.24\times 10^4\ volts$

So, the potential difference through which an electron accelerates to produce x rays is $1.24\times 10^4\ volts$ . hence, this is the required solution.

4 0

3 years ago

Plzzz give me the answer of question no 40 very fast ots soo urgent

mojhsa [17]

R because A-B has 7R but C-d only has 6r so you need to add another r

7 0

3 years ago

Approximately, What is the value of the Hubble Constant, as measured by scientists? Hypothetically, if the value of the Hubble C

Serhud [2]

Answer:

The current value of the Hubble's constant = 73 km/sec/Mpc.

t = 71.9 trillion years will be the new age of universe if the Hubble constant = 700 km/s/Mpc

Explanation:

The current value of the Hubble's constant = 73 km/sec/Mpc. However, recent discoveries in the cosmology contradicts the idea of Hubble constant as being fixed. Some scientists are not agreeing on this value and the debate is going on.

Hubble law states that how fast universe is expanding or in other words, galaxies are expanding separating with a speed directly proportional to the distance of galaxies to the earth.

Hence,

v is directly proportional to d

where, v = apparent velocity

d = distance

if we equate velocity and distance then there comes Hubble constant.

v = $H_{0}$ x d

$H_{0}$ = 73 km/sec/Mpc

where, Mpc = Mega Parsec = 1 Mpc = 3.086 x $10^{19}$ km

We can use Hubble constant to tell the age of universe.

t = d/v

t = d/( $H_{0}$ xd)

t = 1/ $H_{0}$

Scientist calculated the age of universe by using Hubble constant, which is 13.4 billion years.

Now, if we hypothetically change the value of Hubble constant,

from $H_{0}$ = 73 km/sec/Mpc to $H_{0}$ = 700 km/sec/Mpc

then the age of universe will be:

t = 1/ $H_{0}$

first convert the units of new $H_{0}$ into 1/s

$H_{0}$ = (700) x (/3.08 x $10^{19}$ )

$H_{0}$ = 227.27 x $10^{-19}$ = 2.27 x $10^{-21}$ 1/s

So,

Age of universe will be:

t = 1/ $H_{0}$ = 1/2.27x $10^{-21}$ 1/s

t = 2.27 x $10^{21}$ s

t = 71.9 trillion years

t = 71.9 trillion years will be the new age of universe if the Hubble constant = 700 km/s/Mpc

6 0

3 years ago

If you push on a wall of a building what will happen

mixas84 [53]

Answer: It will push back with an equal amount of force.

8 0

3 years ago