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nordsb [41]
3 years ago
12

1.A wagon with a mass of 20 kg is accelerating at 0.5 m/s2. What is the force on it?

Physics
1 answer:
erik [133]3 years ago
3 0

1). Force = (mass) x (acceleration)

Force = (20 kg) x (0.5 m/s )

Force = <em>10 Newtons</em>

2). Force = (mass) x (acceleration)

In this case, the acceleration is the acceleration of gravity.

1 N = (mass) x (9.8 m/s )

Mass = (1 N) / (9.8 m/s )

Mass = <em>0.1 kg</em>

<em></em>

3).  Force = (mass) x (acceleration)

This formula is important. Memorize it !

You saw here that the same formula answered both of your questions.

It'll answer a lot more Physics questions that you haven't seen yet.

If you're taking a Physics class, there will DEFINITELY be at least one question on the final exam that will test you to see whether you know this formula and how to use it. Maybe more than one.

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A well-trained athlete can run 400m in 47s, what is the athlete’s velocity?
AnnZ [28]

Answer:

8.51 m/s

Explanation:

Velocity = Displacement/Time

Velocity = 400 m ÷ 47 s

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7 0
2 years ago
Use the drop-down menus to complete the statement.
VashaNatasha [74]

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7 0
3 years ago
Read 2 more answers
the specific heat of water is 4.2 j/c. if it takes 31,500 joules to heat to warm 750 g of water, what was the temperature change
defon
The amount of heat needed to increase the temperature of a substance by \Delta T is given by
Q=mC_s \Delta T
where
m is the mass of the substance
C_s the specific heat capacity
\Delta T the increase in temperature

In our problem, the mass of the water is m=750 g, the specific heat is C_s = 4.2 J/g ^{\circ}C and the amount of heat supplied is Q=31500 J, so if we re-arrange the previous formula we find the increase in temperature of the water:
\Delta T= \frac{Q}{m C_s}= \frac{31500 J}{(750 g)(4.20 J/g^{\circ} C)}=10^{\circ}C
7 0
3 years ago
A force of 265.1 N acts on an object to produce an acceleration of 14.52 m/s^2. What is the mass of the object?
astra-53 [7]

The answer is :


18.26


Hope I helped.

6 0
3 years ago
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Suppose that two point charges, each with a charge of +1.00 C, are separated by a distance of 1.0 m. If the distance between the
Aleksandr-060686 [28]

Given:

The magnitude of each charge is q1 = q2 = 1 C

The distance between them is r = 1 m

To find the force when distance is doubled.

Explanation:

The new distance is

\begin{gathered} r^{\prime}=\text{ 2r} \\ =2\times1 \\ =2\text{ }m \end{gathered}

The force can be calculated by the formula

F=k\frac{q1q2}{(r^{\prime})^2}

Here, k is the constant whose value is

k=9\times10^9\text{ N m}^2\text{ /C}^2

On substituting the values, the force will be

\begin{gathered} F=9\times10^9\times\frac{1\times1}{(2)^2} \\ =2.25\times10^9\text{ N} \end{gathered}

7 0
1 year ago
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