-28-(-24)=-4
14-18=-4
28-32=-4
Any of these should work and there are plenty more that would work as well
Answer and Explanation:
Using trig ratios, we can express the given values of sin u and tan v as shown below
![\begin{gathered} \sin u=\frac{opposite\text{ of angle u}}{\text{hypotenuse}}=\frac{2}{5} \\ \tan v=\frac{opposite\text{ of angle v}}{\text{hypotenuse}}=\sqrt[]{21} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20%5Csin%20u%3D%5Cfrac%7Bopposite%5Ctext%7B%20of%20angle%20u%7D%7D%7B%5Ctext%7Bhypotenuse%7D%7D%3D%5Cfrac%7B2%7D%7B5%7D%20%5C%5C%20%5Ctan%20v%3D%5Cfrac%7Bopposite%5Ctext%7B%20of%20angle%20v%7D%7D%7B%5Ctext%7Bhypotenuse%7D%7D%3D%5Csqrt%5B%5D%7B21%7D%20%5Cend%7Bgathered%7D)
So we can go ahead and label the sides of the triangle as shown below;
We can find the value of u as shown below;

We can find v as shown below;
We know that for each triangle made up by dashed line segment forms 30° angles, so, for example, ∠GOH is 30° and then ∠HOI is 30°
Rotating the shape 240° around the centre is the same as counting in 30°
The triangle GOH will first fit the triangle HOI then triangle IOJ and so on until it has completed 8 times 30° turn. Its final position is shown in the diagram below