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Makovka662 [10]
3 years ago
14

2. Write a recursive formula for the sequence 5, 18, 31, 44, 57, ... Then find the next term.

Mathematics
2 answers:
ludmilkaskok [199]3 years ago
8 0

Answer: a6=70

Step-by-step explanation:

we know that

In the Arithmetic Sequence the formula is:

an= a1 + d(n−1)

where

a1 is the first term

d is the common difference

n is the number of terms

in this problem

a1=5

a2=18

a3=31

a4=44

a5=57

so

d=a2-a1 or a3-a2 or a4-a3 or a5-a4

d=57-44----> 13

find a6

a6= a1 + d(n−1)

n=6

d=13

a1=5

a6=5+13*(6-1)----> a6=5+13*5----> a6=70

Wittaler [7]3 years ago
3 0

Answer:

<h3>A1=5;an=an-1+13. The next term is 70</h3>

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A line passes through the points (–5, 2) and (10, –1). Which is the equation of the line?
LenKa [72]
We have y - 2 = m(x + 5), where m = (-1 - 2)/(10 + 5) = -3/15 = -1/5;
Then y - 2 = (-1/5)(x + 5);
5y - 10 = (-1)(x + 5);
5y - 10 = -x - 5;
x + 5y - 5 = 0 is the equation of the line.
3 0
3 years ago
HELP I WILL MARK AS BRAINLIEST
umka21 [38]

Answer:

<h3>Postulates and Theorems</h3>

A postulate is a statement that is assumed true without proof. A theorem is a true statement that can be proven. Listed below are six postulates and the theorems that can be proven from these postulates.

Postulate 1: A line contains at least two points.

Postulate 2: A plane contains at least three noncollinear points.

Postulate 3: Through any two points, there is exactly one line.

Postulate 4: Through any three noncollinear points, there is exactly one plane.

Postulate 5: If two points lie in a plane, then the line joining them lies in that plane.

Postulate 6: If two planes intersect, then their intersection is a line.

Theorem 1: If two lines intersect, then they intersect in exactly one point.

Theorem 2: If a point lies outside a line, then exactly one plane contains both the line and the point.

Theorem 3: If two lines intersect, then exactly one plane contains both lines.

Example 1: State the postulate or theorem you would use to justify the statement made about each figure.

(a)

Through any three noncollinear points, there is exactly one plane (Postulate 4).

(b)

Through any two points, there is exactly one line (Postulate 3).

(c)

If two points lie in a plane, then the line joining them lies in that plane (Postulate 5).

(d)

If two planes intersect, then their intersection is a line (Postulate 6).

(e)

A line contains at least two points (Postulate 1).

(f)

If two lines intersect, then exactly one plane contains both lines (Theorem 3).

(g)

If a point lies outside a line, then exactly one plane contains both the line and the point (Theorem 2).

(h)

If two lines intersect, then they intersect in exactly one point (Theorem 1).

3 0
3 years ago
Here is the next one
gizmo_the_mogwai [7]

Answer:

15 students per teacher

10 students per tutor

11 tutors

Step-by-step explanation:

75/5=15

60/6=10

110/10=11

5 0
3 years ago
Use the image to help me answer
melamori03 [73]
It’s b .................
3 0
4 years ago
Read 2 more answers
Anyone that can help me with this?
mrs_skeptik [129]
If a rational function is not continuous, it'll be due to one of two reasons. Either it has a hole, or it has an asymptote. Plug in -5 for x in the denominator of the rational function. What do you get? You get zero in the denominator, meaning the function is undefined at x=-5.
4 0
4 years ago
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