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natita [175]
2 years ago
11

Graph the circle (x+5)^2+(y+2)^2=4

Mathematics
1 answer:
Verizon [17]2 years ago
6 0

(x+5)² + (y+2)² = 4

(x - x0)² + (y - y0)² = r²

with circle center point (x0 ; y0) and r for circle radius

so you have to place the point (- 5 ; - 2) and graph the circle with r = 2

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Construct the exponential function that contains the points (0,2) and (3,54)
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The exponential function that passes through (0,2) and (3,54) is a growth function

The exponetial function is y = 2 * 3^x

<h3>How to construct the exponential function?</h3>

The points are given as:

(x,y) = (0,2) and (3,54)

An exponential function is represented as:

y = ab^x

Substitute the points in the equation

2 = ab^0 and 54 = ab^3

Solve 2 = ab^0

a = 2

Substitute 2 for a in 54 = ab^3

54 = 2b^3

Divide by 2

27 = b^3

Take the cube roots of both sides

b = 3

So, we have:

y = ab^x

This becomes

y = 2 * 3^x

Hence, the exponetial function is y = 2 * 3^x

Read more about exponential functions at:

brainly.com/question/24077767

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Step-by-step explanation:

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Step-by-step explanation:

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