HELPPP!!!!! PLEASEEE

A local park has a grassy playground that is 3/5 mile long and 1/3 mile wide. What part of a square mile does the playground cov

adell [148]

Answer:

The playground covers $\frac{1}{5}$ of a square mile

Step-by-step explanation:

The playground is a rectangular ground. The area of a rectangle is given by legth * width, hence,

The area of the playground is length * width

Area = $\frac{3}{5}*\frac{1}{3}=\frac{3}{15}=\frac{1}{5}$ sq. mi

Hence the playground cover $\frac{1}{5}$ of a square mile

5 0

3 years ago

Can anybody help me with this question?

Rom4ik [11]

Answer:

d

Step-by-step explanation:

it will dialet rectangle b and translate it to be like it

5 0

3 years ago

Read 2 more answers

Hello! I’m a hijabi and today was my first day at a new school. Students make me feel insecure and weird. How should I make some

tatiyna

Answer:

Hi! i think that you should just try and find people who you think are cool are have some of the same intrests! dont let anyone bring you down, you are awesome and make sure to drink water and stay healthy! have a nice day/night!^^ :)

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

The sum of two consecutive even integers is 530. Find the integers.

joja [24]

The 2 numbers are 264 and 266. 264+266=530.

8 0

3 years ago

1. (10 marks) A study of the home purchasing habits of Canadians in show homes found the following interesting facts. The probab

Butoxors [25]

Answer:

$1 a. P(X=1)=0.3809\\\\b. P(X\geq 1)=0.5721\\c. \mu_x=0.81, \ \ \ \sigma_x=0.7371\\d. Increase \ n$

$2.a. 0.2438\\b. 0.6227\\c. \mu_8=17.6, \ \sigma_8=4.1952$

Step-by-step explanation:

The purchase of a house has binomial distribution with p=9% and n=9

a. To find the probability of one house being sold:

$p(x)={n\choose x}p^x(1-p)^{n-x}$

The value of x is 1:

$p(x)={n\choose x}p^x(1-p)^{n-x}\\\\\\P(X=x)={9\choose 1}0.09(1-0.09)^8\\\\=0.3809$

Hence, the probability that one house is sold that day is 0.3809

b.The probability of at least one house is the same as the 1 minus the probability that no house was sold:

$p(x)={n\choose x}p^x(1-p)^{n-x}\\\\P(X\geq 1)=1-P(X=0)\\\\=1-{9\choose 0}0.09^0(0.91)^9\\\\=1-0.4279\\\\=0.5721$

Hence,the probability that at least one house is sold that day is 0.5721

c. The mean of a binomial distribution is the product of the number of events times the probability of success=np

From a above, n=9 and p=0.09:

$\mu_x=np, \ n=9 , \ p=0.09\\\\=9\times 0.09\\\\=0.81$

#The standard deviation is calculated as np(1-p):

$\sigma_x=np(1-p),\ n=9, p=0.09\\\\=9\times 0.09\times 0.91\\\\=0.7371$

Hence, the distribution has a mean of 0.81 and a standard deviation of 0.7371

d. Given that the probability of success is low, the overall successful events can only be increased by increasing the sample size, say n should be increased to 1000.

2. a.Given a Poisson distribution with mean=2.2

-The probability in a Poisson distribution is expressed as:

$P(x;\mu)=\frac{e^{-\mu}\mu^x}{x!}$

The probability of one person showing up is calculated as:

$P(x;\mu)=\frac{e^{-\mu}\mu^x}{x!}\\\\P(1,2.2)=\frac{e^{-2.2}2.2^1}{1!}\\\\=0.2438$

Hence , the probability that exactly one person shows up during a 1-hour period is 0.2438

b. the probability that at most 2 people will show up during a 1-hour period is calculated as:

$P(x;\mu)=\frac{e^{-\mu}\mu^x}{x!}\\\\P(x\leq2 ;\mu)=P(x=0;\mu)+P(x=1;\mu)+P(x=2 ;\mu)\\\\=\frac{e^{-2.2}2.2^0}{0!}+\frac{e^{-2.2}2.2^1}{1!}+\frac{e^{-2.2}2.2^2}{2!}\\\\=0.1108+0.2438+0.2681\\\\=0.6227$

Hence,the probability that at most 2 people will show up during a 1-hour period is 0.6227

c. The mean and variance of a Poisson distribution is equal:

$E(X)=\mu=Var(X)=\sigma^2, \mu=2.2\\\\8E(X)=8(2.2)=\mu_8\\\\\mu_8=17.6\\\\V(X)=\sigma^2=17.6\\\\\sigma=4.1952$

Hence the mean after 8 hrs is 17.6 and the standard deviation will be 4.1952

6 0

3 years ago