Answer:
a. (3x^4 + 6 ) + (2x^2)
b. (X^3 ) + (-x -7)
c. (4.6x^4) + (-1.5x^2)
Step-by-step explanation:
For the first one, we have to write to polynomials, which equal 3x^4 + 2x^2 +6
One possible solution is (3x^4 + 6 ) + (2x^2)
For b, we can do,
(X^3 ) + (-x -7)
And finally for c, we can write,
(4.6x^4) + (-1.5x^2)
Answer:
f(x) = 2x^2 - 3x + 1
Step-by-step explanation:
The root 1 is associated with the factor (x - 1).
The root 1/2 is associated with the factor (x - 1/2), which in turn is equivalent to (2x -1)
The quadratic in question is f(x) = (x - 1)(2x - 1). To write this in standard form, perform the indicated multiplication:
f(x) = 2x^2 - 2x - x + 1, or f(x) = 2x^2 - 3x + 1
Answer:
k = 8
Step-by-step explanation:
8(10 - k) = 2k
First, distribute within the parenthesis,
80 - 8k = 2k
Add 8k to both sides of the equation
80 = 10k
Divide both sides by 10 to get your answer
8 = k
I hope this helps :)
Answer:
both problems are proportional
Answer:
Step-by-step explanation:
What is the answer tho
