PEMDAS
P- none
E- none
M- none
D- (3/1/3=1)
AS- 9-1+1=9
The answer is A.
Answer:
c=-2
Step-by-step explanation:
Hello.
In order to solve this equation, we need to isolate the variable (in this case, the variable is x)
The first step is to use the Distributive Property and distribute 3:


Now, add 3 to both sides:



Now, subtract 2x from both sides:


Therefore, the answer is

I hope it helps.
Have a nice day.

Answer:
B. 6.3%
Step-by-step explanation:
For each time that the coin is tosse, there are only two possible outcomes. Either it comes up tails, or it does not. The probability of coming up tails on a toss is independent of any other toss. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
Fair coin:
Equally as likely to come up heads or tails, so 
Probability that the first tails comes up on the 4th flip of the coin?
0 tails during the first three, which is P(X = 0) when n = 3.
Tails in the fourth, with probability 0.5. So



0.0625 * 100 = 6.25%
Rounding to the nearest tenth of a percent, the correct answer is:
B. 6.3%