First you need to solve for angle F then you can use 1/2acSinB. If you haven't done this you can also use the Pythagoras theorem and solve for the unknown side once you do that you can just use 1/2 b*h

8 0

3 years ago

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Find the greatest common factor of the following monomials 26n5 12n2

Sidana [21]

The greatest common factor is 2 $n^{2}$

We first have to look for the largest number that goes into both equations. The factors of 12 are 1, 2, 3, 4, 6 and 12. None of 3, 4, 6, or 12 go into 26 evenly. So 2 is the largest number you can take out.

With the variables, we take out as many as the lowest number will let us. Since the smallest number of n's is 2 in the second term, we take that many.

8 0

3 years ago

Consider the figure in the diagram above. ABJK is a rectangle. There are two semicircles cut out of the rectangle. AB=8cm; AJ=18

RUDIKE [14]

First find the area of the rectangle, then remove the circular area.

AB * AJ = 8 * 18 = 144 sq cm

Circle = $\pi r^{2}$
= $\pi 4^{2}$
=3.14 * 16
=50.24 sq cm

144 - 50.24 = 93.76 sq cm shaded area.

3 0

3 years ago

- - Use the Quadratic Formula to solve the equation x2 – 2x = -9.​

- - Use the Quadratic Formula to solve the equation x2 – 2x = -9.