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Alenkinab [10]
2 years ago
11

Can someone help me out please

Mathematics
1 answer:
sveticcg [70]2 years ago
3 0
Mucopolysaccharidosis
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20b^7 sqrt(-3)

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Mario surveyed the 17 healthiest patients in the hospital.
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8 0
3 years ago
A number is selected from the set (1, 2, 3, 5, 15, 21, 29, 38, 500). If equal elemental probabilities are assigned, what is
Katen [24]

Answer:

\frac{7}{9} OR 77.78%

Step-by-step explanation:

So, we first need to find out how many numbers fit the "less than 29 or odd" group.

This would be: 1, 2, 3, 5, 15, 21, and 29, which is a total of 7 numbers.

Next, we figure out the total amount of numbers in the population.

This would be: 1, 2, 3, 5, 15, 21, 29, 38, and 500, which is a total of 9 numbers.

Finally, we put the first number (7) over the total (9) = \frac{7}{9}

\frac{7}{9} is now able to be written in a percentage, if you need.

The probability is \frac{7}{9} OR 77.78%

5 0
3 years ago
Hhelp me pleaseeeeee
svetlana [45]

A. Area = ½b × h

= ½ × 16 × 9

= 72

B. Area = b × h

= 26 × 18

= 468

C. Area = a²

= 11²

= 121

D. Area = ½(a+b) × h

= ½(6+21) × 8

= 108


Hope this helps :)

Please consider marking my answer the brainliest!

4 0
3 years ago
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