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Alenkinab [10]
2 years ago
11

Can someone help me out please

Mathematics
1 answer:
sveticcg [70]2 years ago
3 0
Mucopolysaccharidosis
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A cone with radius 2 and height 9 has its radius tripled. How many times greater is the volume of the larger cone than the small
SpyIntel [72]

Answer:

When increasing the radius 3 times the volume increases 9 times and when it is reduced to a third the volume decreases 9 times

Step-by-step explanation:

We have that the formula for the volume of a cone is:

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We first calculate the original volume, where the radius is 2 and the height is 9, replacing:

Vc = 3.14 * (2 ^ 2) * 9

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Now if the radius is tripled it would be: 2 * 3 = 6, the radius would be 6, replacing:

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If we compare:

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This means that when the radius is tripled, the volume increases 9 times.

When if re reduces to a third the radius would be: 2/3, replacing:

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Vc = 12.56

113.04 / 12.56 = 9

Which means that by reducing it to a third the volume becomes 9 times smaller.

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