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stellarik [79]
3 years ago
12

How would you do this?

Mathematics
2 answers:
Semenov [28]3 years ago
8 0
Wouldn't it just be 6?
sdas [7]3 years ago
7 0
You can't:)
destroy the paper
(*´・v・)ε/̵͇̿̿/'̿̿ ̿ ̿ ̿ ̿ ̿
You might be interested in
PLEASE HELP!!!
storchak [24]
1. 7.00
2. A. <span>Sarah is paying the smaller price of $1.25 per cupcake. 

</span>
6 0
3 years ago
A bakery finds that the price they can sell cakes is given by the function p = 580 − 10x where x is the number of cakes sold per
HACTEHA [7]

Answer:

A) Revenue function = R(x) = (580x - 10x²)

Marginal Revenue function = (580 - 20x)

B) Fixed Cost = 900

Marginal Cost function = (300 + 50x)

C) Profit function = P(x) = (-35x² + 280x - 900)

D) The quantity that maximizes profit = 4

Step-by-step explanation:

Given,

The Price function for the cake = p = 580 - 10x

where x = number of cakes sold per day.

The total cost function is given as

C = (30 + 5x)² = (900 + 300x + 25x²)

where x = number of cakes sold per day.

Please note that all the calculations and functions obtained are done on a per day basis.

A) Find the revenue and marginal revenue functions [Hint: revenue is price multiplied by quantity i.e. revenue = price × quantity]

Revenue = R(x) = price × quantity = p × x

= (580 - 10x) × x = (580x - 10x²)

Marginal Revenue = (dR/dx)

= (d/dx) (580x - 10x²)

= (580 - 20x)

B) Find the fixed cost and marginal cost function [Hint: fixed cost does not change with quantity produced]

The total cost function is given as

C = (30 + 5x)² = (900 + 300x + 25x²)

The total cost function is a sum of the fixed cost and the variable cost.

The fixed cost is the unchanging part of the total cost function with changing levels of production (quantity produced), which is the term independent of x.

C(x) = 900 + 300x + 25x²

The only term independent of x is 900.

Hence, the fixed cost = 900

Marginal Cost function = (dC/dx)

= (d/dx) (900 + 300x + 25x²)

= (300 + 50x)

C) Find the profit function [Hint: profit is revenue minus total cost]

Profit = Revenue - Total Cost

Revenue = (580x - 10x²)

Total Cost = (900 + 300x + 25x²)

Profit = P(x)

= (580x - 10x²) - (900 + 300x + 25x²)

= 580x - 10x² - 900 - 300x - 25x²

= 280x - 35x² - 900

= (-35x² + 280x - 900)

D) Find the quantity that maximizes profit

To obtain this, we use differentiation analysis to obtain the maximum point of the Profit function.

At maximum point, (dP/dx) = 0 and (d²P/dx²) < 0

P(x) = (-35x² + 280x - 900)

(dP/dx) = -70x + 280 = 0

70x = 280

x = (280/70) = 4

(d²P/dx²) = -70 < 0

Hence, the point obtained truly corresponds to a maximum point of the profit function, P(x).

This quantity demanded obtained, is the quantity demanded that maximises the Profit function.

Hope this Helps!!!

8 0
3 years ago
Sentence.
Zarrin [17]

Answer:

25

Step-by-step explanation:

We need to set up a system of equations, then solve for the number of board markers.

Let r represent red pens, let b represent board markers.

She has 41 items, so our first equation is r+b=41.

The total cost is $46.30, so our second equation is .55r+1.5b=46.3.

r+b=41

.55r+1.5b=46.3

Let's use substitution.

r+b=41

r=41-b

.55r+1.5b=46.3

.55(41-b)+1.5b=46.3

22.55-.55b+1.5b=46.3

22.55+.95b=46.3

.95b=23.75

b=25

He bought 25 board markers.

6 0
3 years ago
Mary’s coffee shop borrowed $9,850 for new chairs and tables. The money was borrowed for 9 months at 9 ¼ % discounted rate, what
Greeley [361]
Let
M---------------> money borrowed -------------> <span>$9,850
r--------------> </span>discounted rate--------> <span>9 ¼=9.25-------> 0.0925
t---------------> time--------> </span><span>9 months=9*30=270 days
D-------------> </span><span>amount of the discount

we know that
D=M*r*t/360=(9850)*(0.0925)*(270/360)=683.34

the answer is $683.34</span>
6 0
3 years ago
2.7 (7.8)??? I don't know how to work this problem...
ruslelena [56]
Just multiply the two, your answer should be 21.06
8 0
3 years ago
Read 2 more answers
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