Total cost=$142
cost of parts=$62
cost paid for labour=$142-$62=$80
According to question,
》cost of labour per hr=$32
which can be written as,
》cost of labour/time=$32
Use cross multiplication,
》time=cost of labour/32
Since cost of labour is 80,
Time=80/32
=2.5hrs
The additive inverse: The usage of addition with a negative number.
The original equation is 21 - 11 = 10
To use the additive inverse, change it so that there is an addition sign.
21 + (-11) = 10
B) -11 is your answer
hope this helps
Answer:
9^3 times 7^2
Step-by-step explanation:
Answer:
(fºg)(x) = x -2
Step-by-step explanation:
f(x) = x + 2
g(x) = x - 4
(fºg)(x) = ( x - 4) + 2
(fºg)(x) = x -2
Answer:
A = 80 S =70
Step-by-step explanation:
#Adults tickets = A
#Students tickets = S
A + S = 150
5A (means the price is $5 times the number of Adult tickets) equals the total amount for all of the Adult tickets altogether
3S (means the price is $3 times the number of Student tickets) equals the total amount for all of the students tickets altogether
5A + 3S = 610 (Means adding the total of all the student tickets plus adult tickets will equal $610 for all tickets sold)
Using both equations now, you can use substitution or elimination to solve for one of the variables. Then you can use the variable to substitute to solve the remaining one.
A + S = 150
5A + 3S = 610
Substitution:
A = 150 - S (Rearrange the first equation by moving S to the other side)
Substitute into the other equation
5 (150 - S) + 3S = 610
750 - 5S + 3S = 610 Combine like terms : -2S = -140
Solve for S = 70
Substitute into A + S = 150 A + (70) = 150
A = 80
