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elena-14-01-66 [18.8K]
3 years ago
6

Calculate the value of x

Mathematics
2 answers:
mr_godi [17]3 years ago
5 0

Answer:

x = 22 \:  \:  degrees

Step-by-step explanation:

127 + 31 + x = 180 \\ 158 + x = 180 \\ x = 180 - 158 \\ x = 22\:  \: degrees

hope this helps

brainliest appreciated

good luck! have a nice day!

Katena32 [7]3 years ago
3 0

Answer:

22⁰

Step-by-step explanation:

By angle sum property :

x + 127 + 31 = 180⁰

x = 180 - 158

x = 22⁰

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Alex purchased a motorbike that costs $3,500. He’ll pay for the motorbike through an installment plan. The installment plan requ
antoniya [11.8K]

Answer:

Alex will pay $3,662

Step-by-step explanation:

To find the total cost, we can make an equation modeling y=mx+b, with y being the total cost, m being the monthly charges, x being the amount of time it takes, and b being the 10% down payment.

After plugging in the numbers to the equation, we get y=276(12)+350.

Now all that is left is to solve the equation as follows:

y=3,312+350

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3 0
4 years ago
Read 2 more answers
Write two numbers neither of which is eight whose greatest common factor is eight
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These work:

4 & 16
16 & 32
12 & 24
16 & 24
4 0
3 years ago
How many ways are there to rearrange the letters ALIVE in such a way that the word EVIL is not contained in the resulting word
Sergio [31]

Answer: 118 combinations.

Step-by-step explanation:

In ALIVE we have 5 letters, rearranging it we have the possible options of:

5 options for the first letter.

4 options for the second letter, as one was already chosen for the first one

3 options for the third letter, as 2 were already chosen.

2 options for the fourth letter.

1 option for the last letter.

The total number of combinations will be equal to the product of the numbers of options for each letter, then we have:

5*4*3*2*1 = 120 combinations.

And the combinations where the word EVIL is formed are:

AEVIL

EVILA

2 combinations, then the total number of combinations such that the word evil is not formed are:

120 - 2 = 118 combinations.

5 0
3 years ago
A health club sold ten memberships in one week for total of $3000. If male memberships cost $300 and female memberships cost $30
Ket [755]

Answer:

Step-by-step explanation:

The reason you haven't gotten an answer to this is because in its current formatting, there is no answer. Here's what I mean:

The first equation is going to be concerning the NUMBER of memberships sold, where m is male and f is female. The total number of memberships was 10:

m + f = 10

Now for the money equation. The total amount of money made from that number of memberships was 3000, where male memberships cost $300 and so do the female memberships, giving us an equation of

300m + 300f = 3000

Go back to the first equation and solve for either m or f. I solved for m in terms of f:

m = 10 - f and sub that into the second equation for m to get:

300(10 - f) + 300f = 3000 and

3000 - 300f + 300f = 3000. Here is where you find the problem. The -300f and the 300f cancel each other out, leaving you with the fact that

3000 = 3000 which it does, but it doesn't give us any viable answer.

I would have to say that since we can't do math on this, that the most credible answer you'll find is that the same number of male and female memberships were sold because 5 male memberships cost $1500 (5 memberships at $300 a piece is $1500) and 5 female memberships also cost $1500.

1500 + 1500 = 3000

6 0
3 years ago
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