Subtract x on both sides the result you divide it by 5
Answer: option 1
Step-by-step explanation: By constructing a 99% confidence interval for population proportion, it implies that the principal is 99% sure that the confidence interval will contain the population proportion.
When we construct confidence interval, we do so to show that the population parameter that we are looking for is present in the interval at a specified confidence level.
First picture)
I: 5x+2y=-4
II: -3x+2y=12
add I+(-1*II):
5x+2y-(-3x+2y)=-4-12
8x=-16
x=-2
insert x=-2 into I:
5*(-2)+2y=-4
-10+2y=-4
2y=6
y=3
(-2,3)
question 6)
I: totalcost=115=3*childs+5*adults
II: 33=adults+childs
33-adults=childs
insert childs into I:
115=3*(33-adults)+5*adults
115=99-3*adults+5*adults
16=2*adults
8=adults
insert adults into II:
33-8=childs
25=childs
so it's the last option
question 7)
a) y<6 and y>2 can also be written as 2<y<6, so solution 3 exist for example
b) y>6 and y>2 can also be written as 2<6<y, so solution 7 exist for example
c) y<6 and y<2 inverse of b: y<2<6, so for example 1
d) y>6 and y<2: y<2<6<y, this is impossible as y can be only either bigger or smaller than 2 or 6
so it's the last option
question 8)
I: x+y=12
II: x-y=6
subtract: I-II:
x+y-(x-y)=12-6
2y=6
y=3
insert y into I:
x+3=12
x=9
(9,3)
question 9)
I: x+y=6
II: x=y+5
if you take the x=y+5 definition of II and substitute it into I:
(y+5)+y=6
which is the second option :)
2 rooms would be 62+42 which is 104
3 rooms would be 104+42 which is 146
4 rooms would be 146+42 which is 188
5 rooms would be 188+42 which is 230
6 rooms would be 230+42 which is 272
but these are the prices including the 20$
without the 20$ the prices would be
2 rooms is 84
3 rooms is 126
4 rooms is 168
5 rooms is 210
6 rooms is 252
What language is this in because I don't understand any of it?
