Sophia has 8 spend on lunch .Does she have enough money for a sandwich a drink and a bag of chips

A charity organization had a fundraiser where each ticket was sold for a fixed price $70. They had to sell a few tickets just to

lina2011 [118]

Answer:

p = 70n -1500

Step-by-step explanation:

The slope-intercept form of the equation is ...

p = 70n +b

We know that p = -800 for n = 10, so we can find b:

-800 = 70·10 +b

-800 -700 = b = -1500

The net profit equation is ...

p = 70n -1500

4 0

3 years ago

The South Coast Air Basin (Los Angeles, Orange, and San Bernardino counties) does not meet the air quality standards for carbon

Archy [21]

Answer:

0.2225 gr/mile

Step-by-step explanation:

Let's work out first the amount of CO sent out in 1990.

The population we estimated in 12.5 million people with a total of driven miles per year of about

12.5 million*8,700 = 108,750 million miles.

With an CO emission factor of 0.9 g per mile, we would have a total of CO emitted rounding 0.9*180,750 = 97,875 million grams

Now, we must estimate the population for 2020.

Since we are assuming an exponential growth, the population in year t is given by a function

$\bf P(t)= Ce^{kt}$

where C and k are constants to be determined.

We can take 1980 as year 0. This way calculations are lighter. 1990 is year 10 and 2020 is year 20.

So P(0) = 10.3 and C=10.3

So far we have

$\bf P(t)= 10.3e^{kt}$

Given that P(10)=12.5

$\bf 10.3e^{k*10}=12.5\rightarrow e^{10k}=\frac{12.5}{10.3}=1.21359\rightarrow \\10k=log(1.21359)\rightarrow k=0.01936$

And the function that models the population growth is

$\bf P(t)= 10.3e^{0.01936t}$

We need P(20)

$\bf P(20)= 10.3e^{0.01936*20}=10.3e^{0.38717}=15.17\;million$

If the miles driven per person per year remains constant at 8700 mi/yr.person, then we have a total miles driven of

15.17*8,700=131,979 million miles, so the CO emitted would be 0.9*131,979=118,781.1 million grams.

The 30% of the CO sent out in 1990 is 0.3*97,875=29,362.5 million grams.

We must reduce 118,781.1 down to 29,362.5

Hence the new CO emission factor would be

29,362.5/131,979 = 0.2225 gr/mile

6 0

3 years ago

A privately owned lake contains two types of game fish, bass and trout. The owner provides two types of food, A and B, for these

Vinvika [58]

Answer:

133 fishes

Step-by-step explanation:

Units of food A = 400 units

Units of food B = 400 units

Fish Bass required 2 units of A and 4 units of B.

Fish Trout requires 5 units of A and 2 units of B.

i. For food A,

total units of food A required = 2 + 5

= 7 units

number of bass and trout that would consume food A = 2 x $\frac{400}{7}$

= 114.3

number of bass and trout that would consume food A = 114

ii. For food B,

total units of food B required = 4 + 2

= 6 units

number of bass and trout that would consume food B = 2 x $\frac{400}{6}$

= 133.3

number of bass and trout that would consume food B = 133

Thus, the maximum number of fish that the lake can support is 133.

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B2x%7D%20%2B%2012%20%3D%20x%20%2B%208%20" id="TexFormula1" title=" \sqrt{2x} + 12

Helga [31]

First note that $x\ge0$ ; otherwise $\sqrt{2x}$ is undefined as long as we're only looking for real solutions.

We can write

$\sqrt{2x}+12=x+8$
$\sqrt{2x}=x-4$
$2x=(x-4)^2$
$2x=x^2-8x+16$
$x^2-10x+16=0$
$(x-8)(x-2)=0$

$\implies x=8,x=2$

4 0

3 years ago

2n-n-4+7n in simplest form

MrMuchimi

<span>2n-n-4+7n in simplest form is found by combining like terms:

(2-1+7)n - 4 = 8n-4, or 4(2n-1)</span>

6 0

3 years ago