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svet-max [94.6K]
2 years ago
14

Solve pls brainliest

Mathematics
1 answer:
zlopas [31]2 years ago
3 0

Answer:

10

Step-by-step explanation:

\frac{-8}{1} * \frac{-5}{4}= \frac{40}{4}= 10

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matteo is centering a poster on the back of the door that is 32 inches wide the poster is 18 1/2 inches wide how far from the ed
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4 years ago
Question 5 (1 point)
Alchen [17]

Answer:

18/12

Step-by-step explanation:

1/3+2/4+4/6

LCM= 12 so,

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8 0
3 years ago
Can anybody help me figure out the area of simple composite figure?
zvonat [6]

Given:

The length of the rectangle = 16 ft

The width of the rectangle = 12 ft

The diameter of the semicircle = 12 ft

To find the area of the given figure.

Formula

  • A=A_{1} +A_{2}

where,

A be the area of the given figure

A_{1} be the area of the rectangle

A_{2} be the area of the semicircle.

  • The area of the rectangle = lb where, l be the length and b be the width
  • Area of the semicircle = \frac{1}{2} \pi r^{2}, r be the radius of the semicircle.

Now,

The radius of the semicircle r = 6 ft

Putting, r=6, l=16 and b= 12 we get,

A_{1} = (16)(12) sq ft

or, A_{1} = 192 sq ft

A_{2} = \frac{1}{2} (3.14)(6^{2} ) sq ft

or, A_{2}=56.52 sq ft

So,

A = 56.52+192 sq ft

A = 248.52 sq ft

Rounding off to the nearest tenth, we get;

A=248.5 sq ft.

Hence,

The area of the composite figure is 248.5 sq ft.

7 0
3 years ago
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