Multiply equation by a power of 10 to write an equation with integer coefficients

Temka [501]

$2 a^{b} * 3a^{b}$
<span><span><span>2<span>(2^2)</span></span>(3)</span><span>(2^2)
</span></span><span><span><span>2<span>(2^2)</span></span>(3)</span><span>(2^2)
</span></span><span>=96</span>

4 0

3 years ago

Read 2 more answers

Josie took a long multiple-choice, end-of-year vocabulary test. The ratio of the number of problems Josie got incorrect to the n

FrozenT [24]

Answer:

A. Josie got 36 correct answers.

B. Josie got 90 correct answers.

C. 8:36 and 20:90

D.6:27, 12:54, 30:135, among others.

e. Multiply both numbers on the ratio by the same constant integer, thereby ensuring that the resulting numbers form a ratio equivalent to the original.

Step-by-step explanation:

Very well, so the statement is that Josie got 2 problems incorrect for every 9 that she got correct. First the ask how many questions she got correct given that she missed 8 question. First, we divide the 8 question she missed by 2. Now have 4 pairs of questions that Josie missed and for every pair that she failed; Josie got 9 questions correctly. Therefore, we multiply 4 pairs of incorrect questions times 9 correct questions. So, if Josie had 8 incorrect questions, she also had 36 correct answers on her test.

In the case that Josie missed 20 questions, we divide them by two again in order to obtain the number of pairs that Josie missed. Now have 10 pairs of questions that Josie missed and for every pair that she failed; Josie got 9 questions correctly. Therefore, we multiply 10 pairs of incorrect questions times 9 correct questions. So, if Josie had 8 incorrect questions, she also had 90 correct answers on her test.

With the information we collected, we can affirm that the ratios 8:36 and 20:90 are equivalents to the original 2:9 that was stated. Other examples of equivalents ratios could be 6:27, 12/54, 30:135, among many others.

To find the equivalent ratios what we need to do is find common multiples of the numbers that conform the ratio. To do so, we can multiply both numbers by the same constant integer, thereby ensuring that the resulting numbers form a ratio equivalent to the original.

Have a nice day! :D

6 0

3 years ago

PLEASE HELP VERY URGENT

worty [1.4K]

Answer:

A. square root of a^2 + b^2 for both answers

Step-by-step explanation:

The first problem, we are given

a^2 + b^2 = c^2

What we do is solve for c.

sqrt(a^2 + b^2) = c

c = sqrt(a^2 + b^2)

For problem 2,

WE can apply the Pythagorean theorem because we have a right triangle.

The equations is

a^2 + b^2 = c^2 like the first problem

Solving gets us

sqrt(a^2 + b^2) = c

c = sqrt(a^2 + b^2)

3 0

2 years ago

The average weight of the class of 35 students was 45 KG. with the admission of a new student the average weight came down to 44

melamori03 [73]

The weight of the new student is 27 kg.

Average weight

= total weight ÷total number of students

<h3>1) Define variables</h3>

Let the total weight of the 35 students be y kg and the weight of the new student be x kg.

<h3>2) Find the total weight of the 35 students</h3>

y= 35(45)

y= 1575 kg

<h3>3) Write an expression for average weight of students after the addition of the new student</h3>

New total number of students

= 35 +1

= 36

Total weight

= total weight of 35 students +weight of new students

= y +x

$44.5 = \frac{y + x}{36}$

<h3>4) Substitute the value of y</h3>

$44.5 = \frac{1575 + x}{36}$

<h3>5) Solve for x</h3>

36(44.5)= 1575 +x

1602= x +1575

<em>Subtract 1575 from both sides:</em>

x= 1602 -1575

x= 27

Thus, the weight of the new student is 27 kg.

7 0

2 years ago

What is the average rating for operative effectiveness for national group for all 5 weeks 3.5 3.5 3.8 3.7 3.4

dsp73

Answer:

3.58

Step-by-step explanation:

You must add up all of the numbers which will get you 17.9

Then divide 17.9 by the total amount of numbers (5) = 3.58

7 0

3 years ago