Determine which reaction has the highest activation energy.

The concentration of glucose inside a cell is 0.12 mM. Outside the cell the concentration of glucose is 12.9 mM. Calculate the c

Alenkasestr [34]

Answer:

The value of he change in Gibbs free energy ΔG = - 18.083 KJ

Explanation:

Given data

The concentration of glucose inside a cell is (P) = 0.12 m M

The concentration of glucose outside a cell is (R) = 12.9 m M

No. of moles = 1.5 moles

The change in Gibbs free energy

ΔG = RT ㏑ $\frac{P}{R}$

ΔG = 8.314 × 310 ㏑ $\frac{0.12}{12.9}$

ΔG = - 12.055 $\frac{J}{mole}$

Since No. of moles = 1.5 moles

Therefore

ΔG = - 12.055 × 1.5

ΔG = - 18.083 KJ

This the value of he change in Gibbs free energy.

7 0

3 years ago

ethylene glycol, commonly used in automobile antifreeze, contains only carbon, hydrogen and oxygen.combustion analysis of a 23.4

Kay [80]

Answer:

Molecular formula of ethylene glycol is C₂H₆O₂.

Explanation:

Given data:

mass of ethylene glycol = 23.4 mg

mass of water = 20.42 mg

mass of carbon dioxide = 33.27 mg

molar mass of ethylene glycol = 62.0 g / mol

Molecular formula of ethylene glycol = ?

Solution:

percentage of carbon = (33.27 mg/ 23.46 mg) × (12 /44) × 100

= (1.4182× 0.27) × 100 = 38.29

percentage of hydrogen = (20.42 mg/ 23.46 mg) × (2 /18) × 100

= (0.8704× 0.11) × 100 = 9.67

percentage of oxygen = 100 - (38.29 + 9.67 )

= 100 - 47.96 = 52.04

Now we will determine the number of grams atoms of carbon, hydrogen and oxygen.

No. of gram atoms of carbon = 38.29 /12 = 3.19

No. of gram atoms of hydrogen = 9.67 / 1 = 9.67

No. of gram atoms of oxygen = 52.04 / 16 = 3.25

Atomic ratio:

C :H :O 3.19/ 3.19 : 9.67 / 3.19 : 3.25 /3.19

C :H :O 1 : 3 : 1

Molecular formula:

Molecular formula = n × (empirical formula)

n = molar mass of compound / empirical formula mass

empirical formula mass= 1 × 12 + 3 × 1 + 1 × 16

empirical formula mass= 12+3 +16 = 31

n = 62 g /mol / 31 = 2

Molecular formula = n × (empirical formula)

Molecular formula = 2 × (CH₃O)

Molecular formula = C₂H₆O₂

6 0

3 years ago

179.1 g of water is in a Styrofoam calorimeter of negligible heat capacity. The initial T of the water is 16.1oC. After 306.9 g

taurus [48]

Answer:

the specific heat of the unknown compound is $c_u=0.412J/g \cdot C$

Explanation:

Generally the change in temperature of water is evaluated as

$\Delta T = T_2 -T_1$

Substituting 16.1°C for $T_1$ and 27.4°C for $T_2$

$\Delta T = 27.4 - 16.1$

$=11.3^oC$

Generally the change in temperature of unknown compound is evaluated as

$\Delta T_u = T_3 -T_2$

Substituting 27.4°C for $T_2$ and 94.3°C for $T_3$

$\Delta T = 94.3 - 27.4$

$=66.9^oC$

Since there is an increase in temperature then heat is gained by water and this can be evaluated as

$H_w = mc_w \Delta T$

Substituting 179.1 g for m , 4.18 J/g.C for $c_w$ (specific heat of water)

$H_w = 4.18 * 179.1 * 11.3$

$= 8459.6J$

Since there is a decrease in temperature then heat is lost by unknown compound and this can be evaluated as

$H_u = m_uc_u \Delta T_u$

By conservation of energy law

Heat lost = Heat gained

Substituting 306.9 g for $m_u$ , 8459.6J for $H_u$

$8459.6 = 306.9 * c_u * 66.9$

Therefore $c_u = \frac{8459.6}{308.9 *66.9}$

$=0.412J/g \cdot C$

4 0

3 years ago

Which element from this portion of the table chemically reacts in a way similar to the way the element chlorine (Cl) reacts? (1)

mina [271]

D. I or Iodine

This is because they are both in the same periodic family (the halogens) and thus the number of valence electrons are the same

4 0

3 years ago

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hello my BEANS i want to know if u r a girl or a boy so if i call u a boy and u r a girl i am not a bad person i am 13 and i am

finlep [7]

Answer:

okie

Explanation:

imma girl

4 0

3 years ago

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