Answer: ribosomes and membranes.
Explanation:
Answer:
(3S)-2-chloro-2,3-dimethylpentane is produced exclusively.
Explanation:
Electrophilic addition to (3S)-2,3-dimethylpent-1-ene proceeds through a carbocationic intermediate.
In the first step, 
adds onto double bond to produce more stable tertiary carbocation. (protonation)
In the second step, 
adds onto carbocation to produce (3S)-2-chloro-2,3-dimethylpentane exclusively.(nucleophilic addition)
So, option (d) is correct.
Answer is: sodium (Na) and iodine (I₂).
<span>
First ionic bonds in this salt are separeted
because of heat:
</span>NaI(l) → Na⁺(l) + I⁻(l).
Reaction of reduction
at cathode(-): Na⁺(l) + e⁻ → Na(l) /×2.
2Na⁺(l) + 2e⁻ → 2Na(l).
Reaction of oxidation
at anode(+): 2I⁻(l) → I₂(l) + 2e⁻.
The anode is positive
and the cathode is negative.
Explanation:
The property of a substance to resist the flow of motion is known as viscosity. And, more is the density of a substance more will be its viscosity.
Whereas, lesser is the density of a substance then it is easy for the substance to move.
This means that more is the viscosity of a substance least will be its flow and when a substance has lesser viscosity then it will readily flow from one point to another.
Thus, we can conclude that the viscosities of several liquids are being compared. All the liquids are poured down a slope with equal path lengths. The liquid with the highest viscosity will reach the bottom last.
Answer:
Atoms are at their most stable when their outermost energy level is either empty of electrons or filled with electrons.
