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Margarita [4]
3 years ago
9

The ratio of atoms of potassium to ratio of atoms of oxygen is

Chemistry
1 answer:
DanielleElmas [232]3 years ago
5 0
The ratio of atoms of potassium to ratio of atoms of oxygen is 2:1
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There are on average 43 g of sugar and 355 mL can of soda please calculate the molarity of sugar in the can of soda the molar ma
vfiekz [6]

Explanation:

Given :

Amount of solute - sucrose (C12H22O11) = 41 g

Amount of solvent -soda  = 355-mL

Molarity of the solution with respect to sucrose= ?

Molarity(M) is a unit of concentration measuring the number of moles of a solute per liter of solution. The SI unit of molarity is mol/L.

Formula to find the molarity of solution :

               Molarity =  

Amount of solvent is given in mL, let’s convert to L :

               1 L = 1000 mL

Therefore, 355 mL in L will be :

                   

               = 0.355 L

We have the amount of solute in g, let’s calculate the number of moles first :

       Number of moles (n) =  

Molar mass of C12H22O11 = 342.29 g/mol.

Therefore, n =  

               = 0.119 moles.

8 0
3 years ago
A hot lump of 39.9 g of iron at an initial temperature of 78.1 °C is placed in 50.0 mL H 2 O initially at 25.0 °C and allowed to
Drupady [299]

Answer : The final temperature of the mixture is 29.6^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron = 0.499J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of iron = 39.9 g

m_2 = mass of water  = Density\times Volume=1g/mL\times 50.0mL=50.0g

T_f = final temperature of mixture = ?

T_1 = initial temperature of iron = 78.1^oC

T_2 = initial temperature of water = 25.0^oC

Now put all the given values in the above formula, we get

(39.9g)\times (0.499J/g^oC)\times (T_f-78.1)^oC=-(50.0g)\times 4.18J/g^oC\times (T_f-25.0)^oC

T_f=29.6^oC

Therefore, the final temperature of the mixture is 29.6^oC

8 0
3 years ago
3.00 moles of nitrogen and 4.00 moles of oxygen are placed in a 35.0 L container at a temperature of 298 K. What is the pressure
Leto [7]

Answer:

i think the answer is c hoped this helped

Explanation:

7 0
3 years ago
A buffer is composed of nh3 and nh4cl. How would this buffer solution control the ph of a solution when a small amount of a stro
Shkiper50 [21]

Answer:

According to Le-chatelier principle, equilibrium will shift towards left to minimize concentration of OH^{-} and keep same equilibrium constant

Explanation:

In this buffer following equilibrium exists -

NH_{3}(aq.)+H_{2}O(l)\rightleftharpoons NH_{4}^{+}(aq.)+OH^{-}(aq.)

So, OH^{-} is involved in the above equilibrium.

When a strong base is added to this buffer, then concentration of OH^{-} increases. Hence, according to Le-chatelier principle, above equilibrium will shift towards left to minimize concentration of OH^{-} and keep same equilibrium constant.

Therefore excess amount of OH^{-} combines with NH_{4}^{+} to produce ammonia and water. So, effect of addition of strong base on pH of buffer gets minimized.

5 0
4 years ago
What is the net Ionic equation of HClO4(aq)+ NaOH(aq) = H2O(l)+ NaClO4(aq)
uranmaximum [27]
H^+(aq) + OH^-(aq) ---> H2O(l) 

<span>Na^+ and ClO4^- are the spectator ions.</span>
7 0
3 years ago
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