Ask question

Ask question

All categories

3 years ago

9

The ratio of atoms of potassium to ratio of atoms of oxygen is

1 answer:

DanielleElmas [232]3 years ago

5 0

The ratio of atoms of potassium to ratio of atoms of oxygen is 2:1

You might be interested in

Hi, i need help.. please

11111nata11111 [884]

4 because of the measurements and the figures starts from 0 to 40

5 0

2 years ago

Almost all energy on Earth came from the blank

pishuonlain [190]

Answer:

sun

Explanation:

5 0

3 years ago

Read 2 more answers

T is possible to produce a perfect crystalline solid that does not contain any vacancies?

Taya2010 [7]

<span>All crystalline solids contain vacancies. In fact, vacancies is one of the properties of a crystalline solids, for their presences is what creates their random (entropic) design. Furthermore, it is near impossible to create any solid matter that does not contain vacancies/defects. Vacancies can be created by the absence of an atom during matter creation; thermal vibrations can create such a defect as well.</span>

3 0

3 years ago

Read 2 more answers

7.23 x 10^24 Al atoms =

andrew11 [14]

Answer:

12.01 moles

Explanation:

6 0

2 years ago

Calculate the enthalpy of reaction for 2CO + O2 → 2CO2. given the following bond energies:

kotegsom [21]

Answer : The enthalpy change for the reaction is 1043 kJ/mol.

Explanation :

The given chemical reaction is:

$2CO+O_2\rightarrow 2CO_2$

As we know that:

The enthalpy change of reaction = E(bonds broken) - E(bonds formed)

$\Delta H=[(2\times B.E_{C\equiv O})+(1\times B.E_{O\equiv O})]-[2\times B.E_{C=O}]$

Given:

$B.E_{C\equiv O}$ = 1074 kJ/mol

$B.E_{O\equiv O}$ = 499 kJ/mol

$B.E_{C=O}$ = 802 kJ/mol

Now put all the given values in the above expression, we get:

$\Delta H=[(2\times 1074kJ/mol)+(1\times 499kJ/mol)]-[2\times 802kJ/mol]$

$\Delta H=1043kJ/mol$

Therefore, the enthalpy change for the reaction is 1043 kJ/mol.

7 0

3 years ago