Answer:
rate = [NO]²[O2]
Explanation:
The rate law for the reaction:
2 NO(g) + O2(g) → 2 NO2(g)
Is expressed in terms of reactants as follows:
rate = [NO]ⁿ[O2]ˣ
<em>Where n and x are the coefficients of the rate law.</em>
<em />
If [NO] is doubled, the rate increased 4 times. That is only possible if:
rate = [NO]²[O2]ˣ
Now, as [NO] is doubled and increased the rate 4 times, and [NO] + [O2] when doubled increased the rate 8 times, doubled [O2] implies increased the rate 2 times. That is only possible is:
<h3>rate = [NO]²[O2]</h3>
<span>When heating copper in the final step, the bright copper color changes to a dull brown. I think this process will make the percent recovery low because a change in color can mean some reacted. Hope this answers the question. Have a nice day.</span>
Answer:
well, chlorine will undergo in a chemical reaction
Explanation:
neon has completed valence shells, so it neither need electron and or it also don't need to donate the electrons. hence it will not participate in any chemical reaction and it is stable in nature.
whereas chlorine need one more electron to complete it's valence shell and in order to be stable , so it will try to gain one electron , hence
it will take place in a chemical reaction
Answer:
v = 2,66x10⁻⁵ P[H₂C₂O₄]
Explanation:
For the reaction:
H₂C₂O₄(g) → CO₂(g) + HCOOH(g)
At t = 0, the initial pressure is just of H₂C₂O₄(g). At t= 20000 s, pressures will be:
H₂C₂O₄(g) = P₀ - x
CO₂(g) = x
HCOOH(g) = x
P at t=20000 is:
P₀ - x + x + x = P₀+x. That means P at t=20000s - P₀ = x
For 1st point:
x = 92,8-65,8 = 27
Pressure of H₂C₂O₄(g) at t=20000s: 65,8-27 = 38,8
2nd point:
x = 130-92,1 = 37,9
H₂C₂O₄(g): 92,1 - 37,9 = 54,2
3rd point:
x = 157-111 = 46
H₂C₂O₄(g): 111-46 = 65
Now, as the rate law is :
v = k P[H₂C₂O₄]
Based on integrated rate law, k is:
(- ln P[H₂C₂O₄] + ln P[H₂C₂O₄]₀) / t = k
1st point:
k = 2,64x10⁻⁵
2nd point:
k = 2,65x10⁻⁵
3rd point:
k = 2,68x10⁻⁵
The averrage of this values is:
k = 2,66x10⁻⁵
That means law is:
v = 2,66x10⁻⁵ P[H₂C₂O₄]
I hope it helps!
