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2 years ago

What is the length of BC? 24 36 48 30

Mathematics

1 answer:

kotykmax [81]2 years ago

7 0

Answer:

48/24

Step-by-step explanation:

You didn't say which one is line BC so I'm going to give you the answer 48 for the entire line but if you are asking for the middle point to end point then it is 24.

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A delivery company has 18 vehicles in its fleet.

Ilia_Sergeevich [38]

Answer: £1517.04

Step-by-step explanation:

The fuel expenses for the vans will be calculated as:

Vans:

Since the average distance travelled per day is 198km and the average distance travelled per litre is 9km, the van would use:

= 198/9

= 22 litres

Since there are 8 vans, they'll use:

= 22 × 8 = 176 liters

Trucks:

Since the average distance travelled per day is 620km and the average distance travelled per litre is 6.2km, the truck would use:

= 620/6.2

= 100

Since there are 10 trucks, they'll use:

= 100 × 10 = 1000 liters

The amount of liters for both the van and the truck will be:

= 176 liters + 1000 liters

= 1176 liters

The fuel cost will then be:

= 1176 × 1£1.29

= £1517.04

6 0

3 years ago

How do you solve 28-2.2x=11.6x-54.8??

malfutka [58]

28 - 2.2x = 11.6x - 54.8
28 + 54.8 = 11.6x + 2.2x
82.8 = 13.8x
82.8 / 13.8 = x
6 = x
or x = 6

6 0

3 years ago

Find the distance between points A = (2, 0) and

allochka39001 [22]

Answer:

9.2

Step-by-step explanation:

You want the distance between A(2, 0) and B(0, 9).

<h3>Distance</h3>

The distance formula is based on the Pythagorean theorem. It tells you the distance between (x1, y1) and (x2, y2) is ...

d = √((x2 -x1)² +(y2 -y1)²)

For the given points, this becomes ...

d = √((0 -2)² +(9 -0)²) = √(4+81) = √85

d ≈ 9.2

The distance between A and B is about 9.2 units.

3 0

2 years ago

What are factorials? And how do you do them in fractions like

Ket [755]

I think that it is 54

4 0

3 years ago

The answer is red show step by step of the pro tem to get the answer

miskamm [114]

In order to rationalize the denominator of each expression, we need to multiply the expression by the same radical in the denominator, this way we can remove the radical from the denominator.

$\frac{5\sqrt{4}}{\sqrt{3}}(\cdot\sqrt{3})=\frac{5\sqrt{4}\sqrt{3}}{(\sqrt{3})^2}=\frac{5\cdot2\cdot\sqrt{3}}{3}=\frac{10\sqrt{3}}{3}$

10)

$-\frac{5}{3\sqrt{2}}(\cdot\sqrt{2})=-\frac{5\sqrt{2}}{3(\sqrt{2})^2}=-\frac{5\sqrt{2}}{3\cdot2}=-\frac{5\sqrt{2}}{6}$

11)

$\frac{2\sqrt{3}}{4\sqrt{5}}(\cdot\sqrt{5})=\frac{2\sqrt{3}\sqrt{5}}{4(\sqrt{5})^2}=\frac{2\sqrt{15}}{4\cdot5}=\frac{\sqrt{15}}{2\cdot5}=\frac{\sqrt{15}}{10}$

12)

$\frac{\sqrt{5}}{\sqrt{2}}(\cdot\sqrt{2})=\frac{\sqrt{5}\sqrt{2}}{(\sqrt{2})^2}=\frac{\sqrt{10}}{2}$

3 0

1 year ago