A water tank contains 12 1/2 ltres of water. Two-fifth of it was (1 mark) consumed. How much of it was left?
1 answer:
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Answer:
41.8 years
Step-by-step explanation:
From
A= 39000
r = 10.5%
P = $ 485
n=12
t = the unknown
t= [ ln(A) - ln(P) ] / n[ln(1 + r/n)]
t= ln 39000 - ln 485/ 12[ln(1+0.105/12)]
t= 10.57 - 6.18/0.105
t= 41.8 years