3 years ago

Please help I’m down bad atm

Mathematics

1 answer:

kogti [31]3 years ago

5 0

Answer:

the answer is an-as-1+1;a,=1

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Find the slope of the line containing the points (2,-5) and (-4,9)

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The slope would be -2 1/3 or -2.3 repeating

Step-by-step explanation:

The first point would be (-4, 9). The next point is (2, -5). We can tell that the slope will be negative, because the x values increased by 6, but the y values decreased by 4.

The slope would be -2 1/3 or -2.3 repeating

I Hope That This Helps! :)

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Willing to brainlist solve 16-17 please during this exam

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Answer:

16. B

17. B

Step-by-step explanation:

16. The intercept form of the parabola is

$y=a(x-x_1)(x-x_2),$

where $x_1, x_2$ are two x-intercepts.

In your case,

$x_1=2\\ \\x_2=-8$

$y=a(x-2)(x-(-8))\\ \\y=a(x-2)(x+8)$

To find <em>a</em>, substitute coordinates of the point (-6,-4) parabola is passing through

$-4=a(-6-2)(-6+8)\\ \\-4=-16a\\ \\a=\dfrac{1}{4}$

and

$y=\dfrac{1}{4}(x-2)(x+8)$

17. The vertex form of the parabola equation is

$-2p(y-k)=(x-h)^2,$

where <em>(h,k)</em> are the coordinates of the vertex and sign "-" because parabola goes down.

In your case, vertex is (2,3), so

$-2p(y-3)=(x-2)^2$

The vertex is 3 units from the focus, then

$\dfrac{p}{2}=3\\ \\p=6$

The equation of the parabola is

$-2\cdot 6(y-3)=(x-2)^2\\ \\y=-\dfrac{1}{12}(x-3)^2+3$

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3 years ago