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3 years ago

10p^(2)- 5pq - 180q^(2)

Mathematics

1 answer:

ololo11 [35]3 years ago

4 0

Add and subtract the second term to the expression and factor by grouping.
5
(
p
+
4
q
)
(
2
p
−
9
q
)

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Please answer this. I would greatly appreciate it

julia-pushkina [17]

Answer:

The length of the side TU is approximately 29.9 feet long.

Step-by-step explanation:

There is a trigonometry law called the law of sines, which states the sine of an angle divided by its opposite side is equivalent to the sine of all the other angles in that right triangle divided by its corresponding opposite side. You can use this law to help you solve for x. By applying the law of sines, you'll get that $\frac{sin(90^{o})}{x} =\frac{sin(42^{o})}{20}$ ⇒ $\frac{x}{sin(90^{o})} = \frac{20}{sin(42^{o})}$ ⇒ $x=\frac{20*sin(90^o)}{sin(42^{o})}$ ⇒ $x=29.9ft.$

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3 years ago

The soccer team won 12 out of 14 games. If this rate continues, how many games will they win if they play a total of 21 games

Gwar [14]

If they won 12 out of 14 games that will be about 85 percent
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4 years ago

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Please solve with explanation (high points)

Dmitrij [34]

Answer:

see the attachment photo!

7 0

2 years ago

CAN YALLL HELPP PLZZ

Dafna1 [17]

4x - y = 2

y = 4x

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3 years ago

Joy recorded the distances she walked each day for five days. How far did she walk in 5 days? Line plot: 3 xs on 1/3 1 x on 1/2

kotykmax [81]

Answer:

$2\frac{1}{6}\approx 2.167$ units.

Step-by-step explanation:

We have been given that Joy recorded the distances she walked each day for five days.

To find the distance traveled be Joy in 5 days we will add the distances covered by Joy each day.

As there are 3 dots on 1/3, this means that Joy traveled 1/3 units on 3 days.

Since there is 1 dot on 1/2 and on dot on 2/3, so this means that Joy walked 1/2 units one day and 2/3 units another day.

Let us add all these distances.

$\text{Total distance walked by Joy in 3 days}=3\times\frac{1}{3}+\frac{1}{2}+\frac{2}{3}$

$\text{Total distance walked by Joy in 3 days}=\frac{1*3}{3}+\frac{1}{2}+\frac{2}{3}$

Let us have a common denominator.

$\text{Total distance walked by Joy in 3 days}=\frac{3*2}{3*2}+\frac{1*3}{2*3}+\frac{2*2}{3*2}$

$\text{Total distance walked by Joy in 3 days}=\frac{6}{6}+\frac{3}{6}+\frac{4}{6}$

$\text{Total distance walked by Joy in 3 days}=\frac{6+3+4}{6}$

$\text{Total distance walked by Joy in 3 days}=\frac{13}{6}$

$\text{Total distance walked by Joy in 3 days}=2\frac{1}{6}$

Therefore, Joy traveled $2\frac{1}{6}\approx 2.167$ units in 5 days.

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4 years ago